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just olya [345]
3 years ago
13

I NEED HELP ASAP IN ON TIMER!!!!

Mathematics
1 answer:
Rina8888 [55]3 years ago
8 0

Answer:

A: square the binomial (x + 3), distribute the negative to the binomial (x2 + 9), simplify the dividend, and then divide

Step-by-step explanation:

I just took the test

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Question 10 of 21
PSYCHO15rus [73]

<u>ANSWER</u>

A. (4,12)

<u>EXPLANATION</u>

The equations are:

10x +2y = 64...(1)

and

3x - 4y = -36...(2)

To eliminate a variable we make the coefficients of that variable the same in both equations.

It is easier to eliminate x.

We multiply the first equation by 2 to get:

20x + 4y = 128...(3)

We add equations (2) and (3).

3x + 20x + 4y - 4y =  - 36 + 128

23x = 92

Divide both sides by 23

\frac{23x}{23}  =  \frac{92}{23}

x = 4

Put x=4 into equation (1).

10(4)+2y = 64

40+2y = 64

2y = 64 - 40

2y = 24

\frac{2y}{2}  =  \frac{24}{2}

y = 12

The solution is (4,12)

6 0
3 years ago
laura family is going on a vacation. they will drive 4,180 miles over the next two weeks. about how many miles will they drive o
I am Lyosha [343]
On average, they drive 2090 miles per week
4 0
3 years ago
Read 2 more answers
(17+8)-6x2 what is the value
zlopas [31]
Pemdas, ok first 17 plus 8 is 15, 6 times 2 is 12 , so 15 minus 12 is 3. answer is 3
6 0
3 years ago
Read 2 more answers
100 points , please help. I am not sure if I did this correct if anyone can double-check me thanks!
Nookie1986 [14]

Step-by-step explanation:

\lim_{n \to \infty} \sum\limits_{k=1}^{n}f(x_{k}) \Delta x = \int\limits^a_b {f(x)} \, dx \\where\ \Delta x = \frac{b-a}{n} \ and\ x_{k}=a+\Delta x \times k

In this case we have:

Δx = 3/n

b − a = 3

a = 1

b = 4

So the integral is:

∫₁⁴ √x dx

To evaluate the integral, we write the radical as an exponent.

∫₁⁴ x^½ dx

= ⅔ x^³/₂ + C |₁⁴

= (⅔ 4^³/₂ + C) − (⅔ 1^³/₂ + C)

= ⅔ (8) + C − ⅔ − C

= 14/3

If ∫₁⁴ f(x) dx = e⁴ − e, then:

∫₁⁴ (2f(x) − 1) dx

= 2 ∫₁⁴ f(x) dx − ∫₁⁴ dx

= 2 (e⁴ − e) − (x + C) |₁⁴

= 2e⁴ − 2e − 3

∫ sec²(x/k) dx

k ∫ 1/k sec²(x/k) dx

k tan(x/k) + C

Evaluating between x=0 and x=π/2:

k tan(π/(2k)) + C − (k tan(0) + C)

k tan(π/(2k))

Setting this equal to k:

k tan(π/(2k)) = k

tan(π/(2k)) = 1

π/(2k) = π/4

1/(2k) = 1/4

2k = 4

k = 2

8 0
3 years ago
{(-3.7).(-5, -8), (-6, -1). (-9, -1), (0, -3) }
zhenek [66]

Answer:

The domain is the set of all the values of x, so it would be -3, -5, -6, -9, 0. The range would be every set of y, so it would be 7, -8, -1, -3. Finally, this relation is indeed a function.

Domain: -3, -5, -6, -9, 0

Range: 7, -8, -1, -3

Is it a function? Yes

4 0
3 years ago
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