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1 answer:
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Answer:
The point P(1,-3) is not a solution to the system.
Step-by-step explanation:
Given
Let a point be P(1,-3)
Here x = 1 ; y = -3
Substituting the values of x,y in the function
For y<x-1
-3 < 1-1
-3<0 (True)
now for,
y>-x+2
-3 > -1 + 2
-3 > 1 (False)
Hence the point is not a solution to the system.
Answer:
(x - 3)² - 16 = 0
Step-by-step explanation:
The equation of a parabola in vertex form is
y = a(x - h)² + k
where (h, k) are the coordinates of the vertex and a is a multiplier
Subtract 7 from both sides
x² - 6x + 7 = 0 ← in standard form
with a = 1, b = - 6
Given a quadratic in standard form then the x- coordinate of the vertex is
= -
= -
= 3
Substitute x = 3 into the equation for y
y = 3² - 6(3) - 7 = 9 - 18 - 7 = - 16 ⇒ (h, k) = (3, - 16)
y = (x - 3)² - 16 = 0