Find the number of ways to purchase 5 different kinds of juices from a selection of 10 juices

1 answer:

8 0

Formula for combinations:
(n!)/(r!(n-r)!)

For you, this is:
10!/(5!(10-5)!) = 10!/5!5! = (10•9•8•7•6•5•4•3•2)/(5•4•3•2)(5•4•3•2) = (10•9•8•7•6)/(5•4•3•2) = 30240/120=252 different ways.

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Pls help<br> First, correct answer will get brainliest

kozerog [31]

Answer:

A for the first one.

Second one, I'm not sure, but I'd guess it'd be A

Step-by-step explanation:

7 0

3 years ago

Which statement about the following equation is true?

spayn [35]

The given expression is

$3x^2 -8x +5 = 5x^2$

We have to find the discriminant first . And for that, first we need to move whole terms of the left side to right side, that is

$5x^2 -3x^2 +8x -5=0$

$2x^2+ 8x -5 =0$

The formula of discriminant is

$D =b^2 -4ac$

Substituting the values of a,b and c, we will get

$D = 8^2 -4(2)(-5)=64+40 = 104$

And since the discriminant is greater than 0, or it is positive so we have two real roots.

Therefore the correct option is B .

7 0

3 years ago

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What is the value of sin20sin30sin40sin80.

Ilya [14]

1,-1,1,-1 is your answer

3 0

3 years ago

Solve the quadratic equation 3x²-3x-1=0?<br>(by using the square method)

ohaa [14]

Answer:

x=1 and x=-1/3

Step-by-step explanation:

$3x^2-2x-1=0\\\\3(x^2-\frac{2}{3}x-\frac{1}{3})=0\\ \\3(x^2-\frac{2}{3}x-\frac{1}{3}+\frac{4}{9})=3(\frac{4}{9})\\ \\ 3(x^2-\frac{2}{3}x+\frac{1}{9})=\frac{4}{3}\\ \\ 3(x-\frac{1}{3})^2=\frac{4}{3}\\ \\(x-\frac{1}{3})^2=\frac{4}{9}\\ \\x-\frac{1}{3}=\pm\frac{2}{3}$