Find the number of ways to purchase 5 different kinds of juices from a selection of 10 juices

1 answer:

8 0

Formula for combinations:
(n!)/(r!(n-r)!)

For you, this is:
10!/(5!(10-5)!) = 10!/5!5! = (10•9•8•7•6•5•4•3•2)/(5•4•3•2)(5•4•3•2) = (10•9•8•7•6)/(5•4•3•2) = 30240/120=252 different ways.

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padilas [110]

Upper Tolerance

Remark

The 11/16 is the only thing that will be affected. The three won't go up or down when we add 1/64 so we should just work with the 11/16. We need only add 11/16 and 1/64 together to see what the upper range is. Later on we can add 3 into the mix.

Solution

Upper Limit

$\dfrac{11}{16} + \dfrac{1}{64}$