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3 years ago

What would the parabola look like if there was a complex solution?

Mathematics

1 answer:

Kaylis [27]3 years ago

3 0

The parabola's vertex would not be on the x-axis or y-axis and there would be no x-intercepts.

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A raft travels down river at a rate of 6 miles per hour. The total distance d in miles that the raft travels is equal to the rat

Fudgin [204]

Answer:

d=6h

Step-by-step explanation:

Speed of the raft= 6 miles per hour

Total distance (d) of the raft= rate × number of hours

d=r*h

Independent variable is the number of hours(h)

Dependent variable is the distance (d)

Equation for the situation

d=r*h

d=distance

r=rate

h=number of hours

From the question,

r=6 miles per hour

Therefore,

The equation is

d=r*h

d=6*h

d=6h

8 0

3 years ago

What’s the largest fraction: 7/8, 5/8, 7/13, and 11/19

garik1379 [7]

Answer:

7/8

Step-by-step explanation:

7/8 = 0.875

5/8 = 0.625

7/13 = 0.538

11/19 = 0.579

So 7/8 is the largest

4 0

3 years ago

Find a formula for the sun S of any three consecutive odd number?

bixtya [17]

Answer:

Let first no. be x

Therefore,

2nd no. is x+1

Third no. is x+2

SUM OF NO.'s=x+x+1+x+2

S=3x+3

S=3(x+1)

8 0

3 years ago

Read 2 more answers

Pls help with this thx

Natalija [7]

1. 55
2. N/A - Sorry. I can’t see the numbers properly.
3. 180

4 0

2 years ago

Steve likes to entertain friends at parties with "wire tricks." Suppose he takes a piece of wire 60 inches long and cuts it into

Alex_Xolod [135]

Answer:

a) the length of the wire for the circle = $(\frac{60\pi }{\pi+4}) in$

b)the length of the wire for the square = $(\frac{240}{\pi+4}) in$

c) the smallest possible area = 126.02 in² into two decimal places

Step-by-step explanation:

If one piece of wire for the square is y; and another piece of wire for circle is (60-y).

Then; we can say; let the side of the square be b

so 4(b)=y

b= $\frac{y}{4}$

Area of the square which is L² can now be said to be;

$A_S=(\frac{y}{4})^2 = \frac{y^2}{16}$

On the otherhand; let the radius (r) of the circle be;

2πr = 60-y

$r = \frac{60-y}{2\pi }$

Area of the circle which is πr² can now be;

$A_C= \pi (\frac{60-y}{2\pi } )^2$

$=( \frac{60-y}{4\pi } )^2$

Total Area (A);

A = $A_S+A_C$

= $\frac{y^2}{16} +(\frac{60-y}{4\pi } )^2$

For the smallest possible area; $\frac{dA}{dy}=0$

∴ $\frac{2y}{16}+\frac{2(60-y)(-1)}{4\pi}=0$

If we divide through with (2) and each entity move to the opposite side; we have:

$\frac{y}{18}=\frac{(60-y)}{2\pi}$

By cross multiplying; we have:

2πy = 480 - 8y

collect like terms

(2π + 8) y = 480

which can be reduced to (π + 4)y = 240 by dividing through with 2

$y= \frac{240}{\pi+4}$

∴ since $y= \frac{240}{\pi+4}$ , we can determine for the length of the circle ;

60-y can now be;

= $60-\frac{240}{\pi+4}$

= $\frac{(\pi+4)*60-240}{\pi+40}$

= $\frac{60\pi+240-240}{\pi+4}$

= $(\frac{60\pi}{\pi+4})in$

also, the length of wire for the square (y) ; $y= (\frac{240}{\pi+4})in$

The smallest possible area (A) = $\frac{1}{16} (\frac{240}{\pi+4})^2+(\frac{60\pi}{\pi+y})^2(\frac{1}{4\pi})$

= 126.0223095 in²

≅ 126.02 in² ( to two decimal places)

4 0

3 years ago