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2 years ago

Helpppppp me please

Mathematics

1 answer:

nataly862011 [7]2 years ago

7 0

Answer:Sure thing? But first what do you need help with and maybe just maybe I will help you with whatever you need help with?

Step-by-step explanation:

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the average rate of change of the function f(x) on the interval -3≤x≤3 is -2.5. If (-3)=14 then which of the following is the va

oksian1 [2.3K]

The average rate of change of f(x) on -3 ≤ x ≤ 3 is given to be

(f (3) - f (-3)) / (3 - (-3)) = -2.5

If f (-3) = 14, then

(f (3) - 14) / (3 + 3) = -2.5

(f (3) - 14) / 6 = -2.5

f (3) - 14 = -15

f (3) = -1

4 0

3 years ago

The price of a technology stock has dropped to $9.79 yesterday. Today. the price fell to $9.68. Find the percentage decrease.

Citrus2011 [14]

The answer is 1.12% decrease
Explanation in image

4 0

3 years ago

What is the area of this trapezoid? Please find the answer and equation.

Troyanec [42]

Answer:

A=a+b

2h=20+8

2·20.4≈285.6

Step-by-step explanation:

5 0

3 years ago

in exercises 15-20 find the vector component of u along a and the vecomponent of u orthogonal to a u=(2,1,1,2) a=(4,-4,2,-2)

Nimfa-mama [501]

Answer:

The component of $\vec u$ orthogonal to $\vec a$ is $\vec u_{\perp\,\vec a} = \left(\frac{9}{5},\frac{6}{5},\frac{9}{10},\frac{21}{10}\right)$ .

Step-by-step explanation:

Let $\vec u$ and $\vec a$ , from Linear Algebra we get that component of $\vec u$ parallel to $\vec a$ by using this formula:

$\vec u_{\parallel \,\vec a} = \frac{\vec u \bullet\vec a}{\|\vec a\|^{2}} \cdot \vec a$ (Eq. 1)

Where $\|\vec a\|$ is the norm of $\vec a$ , which is equal to $\|\vec a\| = \sqrt{\vec a\bullet \vec a}$ . (Eq. 2)

If we know that $\vec u =(2,1,1,2)$ and $\vec a=(4,-4,2,-2)$ , then we get that vector component of $\vec u$ parallel to $\vec a$ is:

$\vec u_{\parallel\,\vec a} = \left[\frac{(2)\cdot (4)+(1)\cdot (-4)+(1)\cdot (2)+(2)\cdot (-2)}{4^{2}+(-4)^{2}+2^{2}+(-2)^{2}} \right]\cdot (4,-4,2,-2)$

$\vec u_{\parallel\,\vec a} =\frac{1}{20}\cdot (4,-4,2,-2)$

$\vec u_{\parallel\,\vec a} =\left(\frac{1}{5},-\frac{1}{5},\frac{1}{10},-\frac{1}{10} \right)$

Lastly, we find the vector component of $\vec u$ orthogonal to $\vec a$ by applying this vector sum identity:

$\vec u_{\perp\,\vec a} = \vec u - \vec u_{\parallel\,\vec a}$ (Eq. 3)

If we get that $\vec u =(2,1,1,2)$ and $\vec u_{\parallel\,\vec a} =\left(\frac{1}{5},-\frac{1}{5},\frac{1}{10},-\frac{1}{10} \right)$ , the vector component of $\vec u$ is:

$\vec u_{\perp\,\vec a} = (2,1,1,2)-\left(\frac{1}{5},-\frac{1}{5},\frac{1}{10},-\frac{1}{10} \right)$

$\vec u_{\perp\,\vec a} = \left(\frac{9}{5},\frac{6}{5},\frac{9}{10},\frac{21}{10}\right)$

The component of $\vec u$ orthogonal to $\vec a$ is $\vec u_{\perp\,\vec a} = \left(\frac{9}{5},\frac{6}{5},\frac{9}{10},\frac{21}{10}\right)$ .

4 0

3 years ago

Charlie runs laps around a track. the table shows how long it takes him to run different numbers of laps. how long will it take

WARRIOR [948]

Answer:

20 (minutes)

Step-by-step explanation:

Look at the first columns, and it tells us that Charlie runs 2 laps in 8 minutes. Then simply divide by two, then you'll get that Charlie runs 1 lap in 4 minutes. So for five laps, multiply 4 by 5, which is 20.

3 0

3 years ago

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