Ask question

Ask question

All categories

3 years ago

10

A spherical ball just fits inside a cylindrical can that is 10 centimeters tall, with a diameter of 10 centimeters. Which expres

sion gives the volume of the sphere, in cubic centimeters?

1 answer:

fgiga [73]3 years ago

3 0

Step-by-step explanation:

Volume:

$volume \: of \: a\: sphere = \frac{4}{3} \pi {r}^{3} \\ = \frac{4}{3} \pi( {5)}^{3}$

You might be interested in

Sorry to the people who were helping me earlier, but I actually don't get this one. I really need help if anyone could help with

Fed [463]

7/12
12/7
1`2/7
7/12

a reciprocal you just flip the fraction

5 0

3 years ago

Read 2 more answers

Bonnie earns $455 a week, and she works 5 days a week. what is her daily wage?

Nostrana [21]

91$ per day you divid 455$ by the 5 days and get 91$

5 0

3 years ago

What is the value of y?

alexira [117]

9514 1404 393

Answer:

y = 8√3

Step-by-step explanation:

In the 30°-60°-90° "special" triangle, the ratio of sides lengths is ...

1 : √3 : 2 = 8 : y : hypotenuse

In order for these ratios to be equal, we must have ...

y = 8√3

__

If you want to solve this using your trig skills, you recognize that ...

Tan = Opposite/Adjacent

tan(30°) = 8/y

y = 8/tan(30°) . . . . where tan(30°) = 1/√3

y = 8√3

4 0

3 years ago

A statistic is said to be unbiased if

xxMikexx [17]

Answer:

A statistic is said to be unbiased if the mean of its sampling distribution is equal to the true value of the parameter being estimated.

Step-by-step explanation:

A parameter is a number that describes the population.

A statistic is a number that describes a sample.

A statistic used to estimate a parameter is unbiased if the mean of its sampling distribution is exactly equal to the true value of the parameter being estimated. For example, the mean of a sample is an unbiased estimate of the mean of the population from which the sample was drawn.

A statistic is biased if its expected value is not equal to the parameter.

8 0

3 years ago

A stack of cards consists of seven red and four blue cards. A second stack of cards consists of eleven red cards. A stack is sel

Ann [662]

Answer:

0.1733 = 17.33% probability the first stack was selected.

Step-by-step explanation:

To solve this question, it is needed to understand conditional probability, and the hypergeometric distribution.

Hypergeometric distribution:

The probability of x sucesses is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of sucesses.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

Conditional probability:

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

Probability of all red cards for the first stack:

For this, we use the hypergeometric distribution, as the cards all chosen without replacement.

7 + 4 = 11 cards, which means that $N = 11$ .

7 red, which means that $k = 7$

3 are chosen, which means that $n = 3$

We want all red, so we find P(X = 3).

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

$P(X = 3) = h(3,11,3,7) = \frac{C_{7,3}*C_{4,0}}{C_{11,3}} = 0.2121$

Conditional probability:

Event A: All red

Event B: From the first stack.

Probability of all red cards:

0.2121 of 50%(first stack)

1 of 50%(second stack). So

$P(A) = 0.2121*0.5 + 1*0.5 = 0.60605$

Probability of all red cards and from the first stack:

0.21 of 0.5. So

$P(A \cap B) = 0.21*0.5 = 0.105$

What is the probability the first stack was selected?

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.105}{0.60605} = 0.1733$

0.1733 = 17.33% probability the first stack was selected.

4 0

3 years ago