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3 years ago

2/3 of all your books are fiction. 1/6 of those are historical fiction. What fraction of all your books are historical fiction?

Mathematics

1 answer:

STALIN [3.7K]3 years ago

6 0

Multiply 2/3 and 1/6
2*1= 2
3*18=54
simplify 2/54 = 1/27

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What number is 2,456 to the zero power?

Jlenok [28]

1
This is the correct answer

3 0

2 years ago

Plz help, will give brainiest

Tems11 [23]

Answer:

4x^2 + 8x + 4

4(x^2 + 2x + 1) - remove GCF of 4

4(x + 1)(x + 1) - factor

4(x + 1)^2 - collect like terms

Step-by-step explanation:

Then also expand it out by distributing:

21x^3 + 35x²

Form 1:

21x^3 + 35x² - unfactored

Form 2:

7x²(3x + 5) - factored with GCF of 7x² brought to the front

Update:

You could also multiply two binomials and make a quadratic.

Example:

(7x + 2)(3x + 5)

7x(3x + 5) + 2(3x + 5)

= 21x² + 35x + 6x + 10

= 21x² + 41x + 10

7 0

2 years ago

a rectangular prism 1/4 centimeter long, 4 centimeters wide, and 1/2 centimeter high. What is the volume, in cubic centimeters,

Hoochie [10]

Answer:

0.5cm^3

Step-by-step explanation:

volume of rectangular prism= length x width x height

1/4cm x 1/2cm x 4cm =

0.25cm x 0.5cm x 4cm =

0.5cm^3

7 0

3 years ago

The semicircle shown at left has center X and diameter W Z. The radius XY of the semicircle has length 2. The chord Y Z has leng

gladu [14]

${\bold{\red{\huge{\mathbb{QUESTION}}}}}$

The semicircle shown at left has center X and diameter W Z. The radius XY of the semicircle has length 2. The chord Y Z has length 2. What is the area of the shaded sector formed by obtuse angle WXY?

$\bold{ \red{\star{\blue{GIVEN }}}}$

RADIUS = 2

CHORD = 2

RADIUS --> XY , XZ , WX

( BEZ THEY TOUCH CIRCUMFERENCE OF THE CIRCLES AFTER STARTING FROM CENTRE OF THE CIRCLE)

$\bold{\blue{\star{\red{TO \: \: FIND}}}}$

THE AREA OF THE SHADED SECTOR FORMED BY OBTUSE ANGLE WXY.

$\bold{ \green{ \star{ \orange{FORMULA \: USED}}}}$

AREA COVERED BY THE ANGLE IN A SEMI SPHERE

$AREA = ANGLE \: \: IN \: \: RADIAN \times RADIUS$

$\huge\mathbb{\red A \pink{N}\purple{S} \blue{W} \orange{ER}}$

Total Area Of The Semi Sphere:-

$AREA = \pi \times radius \\ \\ AREA = \pi \times 2 = 2\pi$

Area Under Unshaded Part .

Given a triangle with each side 2 units.

This proves that it's is a equilateral triangle which means it's all angles r of 60° or π/3 Radian

So AREA :-

$AREA = \frac{\pi}{3} \times radius \\ \\ AREA = \frac{\pi}{3} \times 2 \\ \\ AREA = \frac{2\pi}{3}$

$\green{Now:- } \\ \green{ \: Area \: Under \: Unshaded \: Part }$

Total Area - Area Under Unshaded Part

$Area= 2\pi - \frac{2\pi}{3} \\ Area = \frac{6\pi - 2\pi}{3} \\ Area = \frac{4\pi}{3} \: \: ans$

$\red \star{Thanks \: And \: Brainlist} \blue\star \\ \green\star If \: U \: Liked \: My \: Answer \purple \star$

5 0

2 years ago

Witch of the following is a true statement about a circle inscribed in a regular polygon

ss7ja [257]

The area of the circle is equal to the area of the polygon

4 0

3 years ago