Answer:
a
Explanation:
jijjijuuuuhuhhhhhhhhhhhhh
Each Celsius degree is the size of 1.8 Fahrenheit degrees. So you need dip your Fahrenheit thermometer into the sample, see where you're starting, and then warm it up to a temperature that reads (37.1 x 1.8) = 66.8 Fahreheit degrees higher.
Well, isn’t v=d/t, then by making subject d, d=vt, turn 3 hours into seconds, 1hr=3600sec, hence 3hr=x, cross multiply and you would have converted it into seconds, then put it into your equation of d=vt
A. To find work we need to know F and S; to find power we need to know F and V
Answer:
1.74 m/s
Explanation:
From the question, we are given that the mass of the an object, m1= 2.7 kilogram(kg) and the mass of the can,m(can) is 0.72 Kilogram (kg). The velocity of the mass of an object(m1) , V1 is 1.1 metre per seconds(m/s) and the velocity of the mass of can[m(can)], V(can) is unknown- this is what we are to find.
Therefore, using the formula below, we can calculate the speed of the can, V(can);
===> Mass of object,m1 × velocity of object, V1 = mass of the can[m(can)] × velocity is of the can[V(can)].----------------------------------------------------(1).
Since the question says the collision was elastic, we use the formula below
Slotting in the given values into the equation (1) above, we have;
1/2×M1×V^2(initial velocity of the first object) + 1/2 ×M(can)×V^2(final velocy of the first object)= 1/2 × M1 × V^2 m( initial velocity of the first object).
Therefore, final velocity of the can= 2M1V1/M1+M2.
==> 2×2.7×1.1/ 2.7 + 0.72.
The velocity of the can after collision = 1.74 m/s
