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olga55 [171]
4 years ago
10

A curve of radius 40 m is banked so that a 1100 kg car traveling at 40 km/h can round it even if the road is so icy that the coe

fficient of static friction is approximately zero. The acceleration of gravity is 9.81 m/s 2 . θ Find the minimum speed at which a car can travel around this curve without skidding if the coefficient of static friction between the road and the tires is 0.2. Answer in units of m/s.
Physics
1 answer:
nikitadnepr [17]4 years ago
6 0

Answer:

9.43 m/s

Explanation:

r = 40 m

v = 40 km/h = 40 x 5 / 18 = 11.11 m/s

g = 9.81 m/s^2

μ = 0.2

Let the minimum speed is v. By using the formula

v² = μ r g

v² = 0.2 x 40 x 11.11 =  88.88

v = 9.43 m/s

Thus, the minimum speed at which the car travel without skidding is 9.43 m/s.

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Explanation:

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If the initial velocity of an object was -2 meters per second
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A :-) for this question , we should apply
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a = -12 by 16
( cut 12 and 16 because 2 x 6 = 12 and
2 x 8 = 16 )
( cut 6 and 8 because 2 x 3 = 6 and
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What factors determine the distance at which two atoms form a bond ?
dsp73

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Explanation:

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