Answer:


Explanation:
t = Time taken = 0.46
u = Initial velocity
v = Final velocity
s = Displacement = 1 m
a = Acceleration

The acceleration due to gravity is 9.45179 m/s²

The function is 
Answer:
60 ft
Explanation:
The tree man and their shadow system forms two similar right angle triangles.
the figure is in the attachment.
let ∠BAC= θ
Therefore, in triangle ABC
tanθ = BC/AC= 35/75= 7/15
now in ΔAEF also
tanθ = EF/AE = 7/75-x= 7/15
solving we get x=60 ft
Now AC and FA are the shadows of the tree and the man respectively.
now FA =75-x=75-60= 15 ft
Therefore, the man must stand at a distance of 60 ft from the tree can you stand and still be completely in the shadow of the tree
Answer:
<u><em></em></u>
- <u><em>1,500 kg.m/s</em></u>
Explanation:
First, arrange the information in a table:
Object Mass (kg) Velocity (m/s)
A 200 15
B 150 - 10
After the collision, the two objects are stick together, thus you talk aobut one object and one momentum.
According to the law of convervation of momentum, the momentum after the collision is equal to the momentum before the collision.
<u>Momentum before the collision, P₁</u>:


<u>Momentum after the collision</u>:
- As stated, it es equal to the momentum before the collision: 1,500 kg . m/s
The first ariplanr was made December 17, 1903
The answer to this question would possibly be E.