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photoshop1234 [79]
3 years ago
14

You work in a materials testing lab and your boss tells you to increase the temperature of a sample by 37.1 ∘c . the only thermo

meter you can find at your workbench reads in degrees fahrenheit.
Physics
1 answer:
Ivahew [28]3 years ago
7 0
Each Celsius degree is the size of 1.8 Fahrenheit degrees. So you need dip your Fahrenheit thermometer into the sample, see where you're starting, and then warm it up to a temperature that reads (37.1 x 1.8) = 66.8 Fahreheit degrees higher.
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In an experiment to estimate the acceleration due to gravity, a student drops a ball at a distance of 1 m above the floor. His l
anyanavicka [17]

Answer:

9.45179\ m/s^2

s=4.725895t^2

Explanation:

t = Time taken = 0.46

u = Initial velocity

v = Final velocity

s = Displacement = 1 m

a = Acceleration

s=ut+\frac{1}{2}at^2\\\Rightarrow 1=0\times 0.46+\frac{1}{2}\times a\times 0.46^2\\\Rightarrow a=\frac{1\times 2}{0.46^2}\\\Rightarrow a=9.45179\ m/s^2

The acceleration due to gravity is 9.45179 m/s²

s=ut+\frac{1}{2}at^2\\\Rightarrow s=\frac{1}{2}at^2\\\Rightarrow s=\dfrac{1}{2}9.45179t^2\\\Rightarrow s=4.725895t^2

The function is s=4.725895t^2

3 0
3 years ago
Suppose you are standing such that a 35-foot tree is directly between you and the sun. If you are 7 feet tall and the tree casts
Juli2301 [7.4K]

Answer:

60 ft

Explanation:

The tree man and their shadow system forms two similar right angle triangles.

the figure is in the attachment.

let ∠BAC= θ

Therefore, in triangle ABC

tanθ = BC/AC= 35/75= 7/15

now in ΔAEF also

tanθ = EF/AE = 7/75-x= 7/15

solving we get x=60 ft

Now AC and FA are the shadows of the tree and the man respectively.

now FA =75-x=75-60= 15 ft

Therefore, the man must stand at a distance of 60 ft from the tree can you stand and still be completely in the shadow of the tree

3 0
4 years ago
The chart show the masses and velocities of two colliding objects that stick together after a collision.
finlep [7]

Answer:

<u><em></em></u>

  • <u><em>1,500 kg.m/s</em></u>

Explanation:

First, arrange the information in a table:

Object        Mass (kg)           Velocity (m/s)

  A                    200                      15

  B                     150                    - 10

After the collision, the two objects are stick together, thus you talk aobut one object and one momentum.

According to the law of convervation of momentum, the momentum after the collision is equal to the momentum before the collision.

<u>Momentum before the collision, P₁</u>:

          P_1=m_{A,1}\times v_{A,1}+m_{B,1}\times v_{B,1}

         P_1=200kg\times 15m/s+150kg\times (-10m/s)\\\\  P_1=3000kg.m/s-1500kg.m/s=1500kg.m/s

<u>Momentum after the collision</u>:

  • As stated, it es equal to the momentum before the collision: 1,500 kg . m/s
6 0
4 years ago
When was the first airplane made?
expeople1 [14]
The first ariplanr was made December 17, 1903
3 0
4 years ago
Read 2 more answers
The speed of sound in air is about 340 m/s. What is the wavelength of sound waves produced by a guitar string vibrating at 512 H
expeople1 [14]
The answer to this question would possibly be E.
3 0
4 years ago
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