Answer:
Explanation:
Given
When we drop an object from height , suppose h
it takes time T
using equation of motion
where
here 
because it dropped from a certain height
When height is increases to three times of original height
i.e. 
then time period becomes
Answer:
The maximum temperature rise = 0.047 °C
Explanation:
Potential Energy, P = mgh
Energy transfered, Q=mcΔT
Potential energy = Energy transfered
mgh = mcΔT
gh = cΔT
ΔT = gh/c
ΔT = (9.81 * 20) / 4186
ΔT = 0.047 °C
Answer:
+ 5 m/s
Explanation:
change in displacement = ΔX=final position - initial position
ΔX = 0-(-5) =0+5 =+ 5 m
average velocity = ΔX/t
= +5/1
= + 5 m/s
positive sign shows that ball rolls towards right
Answer:
a) 2nd case rate of rotation gives the greater speed for the ball
b) 1534.98 m/s^2
c) 1515.04 m/s^2
Explanation:
(a) v = ωR
when R = 0.60, ω = 8.05×2π
v = 0.60×8.05×2π = 30.34 m/s
Now in 2nd case
when R = 0.90, ω = 6.53×2π
v = 0.90×6.53×2π = 36.92 m/s
6.35 rev/s gives greater speed for the ball.
(b) a = ω^2 R = (8.05×2π)^2 )(0.60) = 1534.98 m/s^2
(c) a = ω^2 R = (6.53×2π)^2 )(0.90) = 1515.05 m/s^2
Answer:
Explanation:
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