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3 years ago

An airplane weighs 18,000lbs. The local gravitational acceleration g is 32fps^2. What is the mass of the airplane?

Physics

1 answer:

Zolol [24]3 years ago

7 0

Answer:

Mass of the airplane, m = 562.5 slugs

Explanation:

Given that,

Weight of the airplane, W = 18,000 lbs

The acceleration due to gravity is, $g=32\ fp/s^2$

Let m is the mass of the airplane. The weight of an object is equal to the product of mass and acceleration due to gravity as :

W = m × g

$m=\dfrac{W}{g}$

$m=\dfrac{18000}{32}$

m = 562.5 slugs

So, the mass of the airplane is 562.5 slugs. Hence, this is the required solution.

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6. Which statement about energy is true? A. Energy is a wave. B. Energy cannot travel through a vacuum. C. Energy has the abilit

GuDViN [60]

Answer:

Explanation:

There is such thing a wave energy, but that doesn't quite fit for this question. B. I have not heard of that, so it has to be incorrect. C. Yes, energy can cause motion in a lot of ways. D. Energy can change forms so that is incorrect.

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3 years ago

Which changes involve forming or breaking chemical bonds?

Ivahew [28]

Answer: burning and melting

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Digestion is a food processing that is ingested into smaller particles that can or can not be assimilated by the body.

Explanation:

3 0

3 years ago

One strategy in a snowball fight is to throw a snowball at a high angle over level ground. Then, while your opponent is watching

agasfer [191]

Answer:

22.5°

Explanation:

<u>Short answer</u>: The trajectories will hit the same target when the projectile is launched at complementary angles. The second angle is 90° -67.5° = 22.5°.

<u>Longer answer</u>: The horizontal speed of the snowball launched at angle α with speed s is ...

vh = s·cos(α)

Then the horizontal distance at time t is ...

x = vh·t

and the time taken to get to some distance x is ...

t = x/vh = x/(s·cos(α))

The equation for the vertical motion of the projectile is ...

y = -4.9t² +s·sin(α)·t

Substituting the above expression for t, we have y in terms of x:

y = -4.9x²/(s·cos(α))² +(s·sin(α)·x)/(s·cos(α))

Factoring gives ...

y = (x/(cos(α))(-4.9x/(s²·cos(α)) +sin(α))

The height y will be zero at x=0 and at ...

0 = -4.9x/(s²·cos(α)) +sin(α)

x = s²·sin(α)·cos(α)/4.9 = (s²/9.8)sin(2α)

So, for some alternate angle β, we want ...

sin(2α) = sin(2β)

We know this will be the case for ...

2β = 180° -2α

β = 90° -α

The second snowball should be thrown at an angle of 90°-67.5° = 22.5° to make it hit the same point as the first.

3 0

3 years ago

A particle is moving in a circular path of radius r . The displacement after half a circle would be

Art [367]

Answer:

Explanation:

As we know that

The displacement is the total distance measured between the initial or start and final or destination point

If particle cover half path of the circle, the displacement can easily find out by considering the distance between the start and destination point

We attached the diagram for better understanding

As per the diagram.

The displacement after half-circle is

AB = OA + OB

= r + r

= 2r

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4 years ago

A plane flying at an altitude of 33,000 feet at a speed of 630 miles per hour releases a bomb. Find the tangential and normal co

Galina-37 [17]

Ignoring air resistance . . .

After the bomb is released, tangential (horizontal) acceleration is zero,, normal (vertical) acceleration is 9.8 m/s^2 down (gravity).

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3 years ago