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3 years ago

In the notation "s(x) = ...," what does "s(x)" represent?

1 answer:

6 0

"s(x)" is the name of a function of one variable, x. The "s" may be mnemonic for whatever the function calculates (speed or side length or surface area, for example), but may not have any particular meaning.

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Find the slope given the coordinates (25 points)

musickatia [10]

1.0.2
2.0.66
3.-1
4.0.42
5.1.4
6.-8
7.5
8.0.54
9.-0.44
10. 0.66
Pls brainliest took me a really long time

6 0

3 years ago

The computer won’t accept my answers and my teacher doesn’t accept late work

LiRa [457]

Email the teacher and see if she can check it at a later time

7 0

2 years ago

ZanzabumX [31]

Note that the scale factor of B to A is (4 / 8) = 1/2

So....the volume of B =

Volume of A * (scale factor)^3 =

2720 * (1/2)^3 =

2720 * 1/8 =

340 cm^3

Hope this helps :)

7 0

3 years ago

Read 2 more answers

The region bounded by y=(3x)^(1/2), y=3x-6, y=0

Ganezh [65]

Answer:

4.5 sq. units.

Step-by-step explanation:

The given curve is $y = (3x)^{\frac{1}{2} }$

⇒ $y^{2} = 3x$ ...... (1)

This curve passes through (0,0) point.

Now, the straight line is y = 3x - 6 ....... (2)

Now, solving (1) and (2) we get,

$y^{2} - y - 6 = 0$

⇒ (y - 3)(y + 2) = 0

⇒ y = 3 or y = -2

We will consider y = 3.

Now, y = 3x - 6 has zero at x = 2.

Therefor, the required are = $\int\limits^3_0 {(3x)^{\frac{1}{2} } } \, dx - \int\limits^3_2 {(3x - 6)} \, dx$

= $\sqrt{3} [{\frac{x^{\frac{3}{2} } }{\frac{3}{2} } }]^{3} _{0} - [\frac{3x^{2} }{2} - 6x ]^{3} _{2}$

= $[\frac{\sqrt{3}\times 2 \times 3^{\frac{3}{2} } }{3}] - [13.5 - 18 - 6 + 12]$

= 6 - 1.5

= 4.5 sq. units. (Answer)

7 0

2 years ago

You have 100 feet of fencing and decide to make a rectangular garden. What is the largest area enclosed

k0ka [10]

Answer:

625 ft^2

Step-by-step explanation:

Given

$P = 100$ --- perimeter

Required

The largest area

The perimeter is calculated as:

$P = 2 * ( L + W)$

So, we have:

$2 * ( L + W) = 100$

Divide both sides by 2

$L + W = 50$

Make L the subject

$L = 50 - W$

The area is calculated as:

$A= L * W$

Substitute $L = 50 - W$

$A= (50 - W) * W$

Open bracket

$A = 50W - W^2$

Differentiate with respect to W

$A' = 50 -2W$

Set to 0; to get the maximum value of W

$50 - 2W = 0$

Collect like terms

$-2W = -50$

Divide by -2

$W = 25$

So, the maximum area is:

$A = 50W - W^2$

$A = 50 * 25 - 25^2$

$A = 1250 - 625$

$A = 625$

3 0

2 years ago