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tangare [24]
3 years ago
12

Tyler has some red blocks and some green blocks. The total weight of 2 red blocks and 6 green blocks is 23 ounces The total weig

ht of 3 red blocks and 4 green blocks is 22 ounces What is the total weight of 1 red block and 1 green block?
Mathematics
1 answer:
bearhunter [10]3 years ago
5 0

Answer: the total weight of 1 red block is 4 ounces and 1 green block is 2.5 ounces.

Step-by-step explanation:

Let x represent the total weight of 1 red block.

Let y represent the total weight of 1 green block.

The total weight of 2 red blocks and 6 green blocks is 23 ounces. This means that

2x + 6y = 23 - - - - - - - - - 1

The total weight of 3 red blocks and 4 green blocks is 22 ounces. This means that

3x + 4y = 22- - - - - - - - - - 2

Multiplying equation 1 by 3 and equation 2 by 2, it becomes

6x + 18y = 69

6x + 8y = 44

Subtracting, it becomes

10y = 25

y = 25/10 = 2.5

Substituting y = 2.5 into equation 1, it becomes

2x + 6 × 2.5 = 23

2x + 15 = 23

2x = 23 - 15 = 8

x = 8/2 = 4

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Write a subtraction sentence using integers.than,write the equivalent addition sentence and explain how to find the sum.please h
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6 0
3 years ago
X+y+z =4
cestrela7 [59]
<span><span> <span>Akar akar persamaan kuadrat 2x² - 3x -1 = 0 adalah x1 dan x2. Persamaan kuadrat baru yang akar akarnya satu lebih kecil dari dua kali akar akar persamaan kuadrat di atas adalah ........</span></span><span><span><span>A.x² - x - 4 = 0</span><span>B.x² + 5x - 4 = 0</span><span>C.x² - x + 4 = 0</span></span><span><span>D.x² + x + 4 = 0</span><span>E.x² - 5x - 4 = 0</span></span></span><span>Jawaban : A
Penyelesaian : 
Akar-akar persamaan lama :  x1 dan x2
                                             
Akar-akar persamaan baru :  xA dan xB
                                             xA = 2x1 - 1
                                             xB = 2x2 - 1
                                             xA + xB  = (2x1 - 1) + (2x2 - 1)
                                                           = 2 (x1 + x2) - 2
                                                           = 2 () - 2
                                                           = 3 - 2
                                              xA + xB = 1
    
                                              xA . xB = (2x1 - 1) (2x2 - 1)
                                                          = 4 x1.x2 - 2(x1 + x2) + 1
                                                          = 4.(-) - 2() + 1
                                                          = -2 - 3 + 1
                                              xA . xB = -4
    
Jadi persamaan kuadrat baru : x² - (xA + xB)x + xA . xB = 0
                                              x² - x - 4 = 0

</span></span>
4 0
3 years ago
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