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babymother [125]
3 years ago
8

The median of 10,31,36,36,38,42,47,48,49,52

Mathematics
1 answer:
olga2289 [7]3 years ago
7 0
So,

To find the median, arrange all the numbers from least to greatest.

10, 31, 36, 36, 38, 42, 47, 48, 49, 52

The middle two numbers are 38 and 42.  Take their average.
40

40 is the median of 10, 31, 36, 36, 38, 42, 47, 48, 49, and 52.
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WHOEVER GETS RIGHT GETS BRAINLIEST!!
ozzi

Answer:

Answer B:  min. value at -6

Step-by-step explanation:

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Note:  Please use " ^ " to denote exponentiation, as shown.

Start with f(x) = x^2 - 2x - 5.

Identify the coefficient of the x term:  it is 2.

Take half of that and square your result:  (1/2)(2) = 1, and then 1^2 = 1.

Add and subtract this 1 between the 2x term and the constant term:

f(x) = x^2 - 2x    + 1   - 1  - 5

Rewrite x^2 - 2x + 1 as a perfect square:

f(x) = (x - 1)^2 - 1 - 5, or    f(x) = (x - 1)^2 - 6

Compare this to the standard form

                                        f(x) = (x - h)^2 + k

We see that h = 1 and k = -6.

The vertex is located at (h, k); here, it's located at (1, -6).

Thus, the minimum value of this function is at the vertex (1, -6).

This agrees with Answer B:  min. value at -6.

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3 years ago
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