I came up with 2 answers 1 I got a Nd 2 I got c
Most likely true. It depends. When the distribution is skewed with an extreme tilting it to one side, median would be a better measure of central tendency. If the extremities are almost balanced on both sides then mean would be a better measure of central tendency.
Y = 1/2 |x - 3| is only answer with the translation of 3 units to the right.
Answer: 1
<span>The assumption that YZ is perpendicular bisector of AX is not enough to show hat YXZ equals YAZ is false</span>
Answer:
2,5,8,11,13,18,22,27,32,48
