Answer:
good luck cause i dont know
Step-by-step explanation:
heheh
If you're asking for extrema, like the previous posting
well

like the previous posting, since this rational is identical, just that the denominator is negative, the denominator yields no critical points
and the numerator, yields no critical points either, so the only check you can do is for the endpoints, of 0 and 4
f(0) = 0 <---- only maximum, and thus absolute maximum
f(4) ≈ - 0.19 <---- only minimum, and thus absolute minimum
If i understood it right when you estimate the quotient it help you have an idea
-6/7 = -x/84
84/7 = 12
12(-6) = -72
x = -72
So, -6/7 = -72/84 because -72/84 simplifies to -6/7
The solution to the equation is p = 1/3 and q = undefined
<h3>How to solve the equation?</h3>
The equation is given as:
p^2 - 2qp + 1/q = (p - 1/3)
The best way to solve the above equation is by the use of a graphing calculator i.e. graphically
However, it can be solved algebraically too (to some extent)
Recall that the equation is given as:
p^2 - 2qp + 1/q = (p - 1/3)
Split the equation
So, we have
p^2 - 2qp + 1/q = 0
p - 1/3 = 0
Solve for p in p - 1/3 = 0
p = 1/3
Substitute p = 1/3 in p^2 - 2qp + 1/q = 0
So, we have
(1/3)^2 - 2q(1/3) + 1/q = 0
This gives
1/9 - 2/3q + 1/q = 0
This gives
2/3q + 1/q = -1/9
Multiply though by q
So, we have
2/3q^2 + 1 = -1/9q
Multiply through by 9
6q^2 + 9 = -q
So, we have
6q^2 + q + 9 = 0
Using the graphing calculator, we have
q = undefined
Hence. the solution to the equation is p = 1/3 and q = undefined
Read more about equations at:
brainly.com/question/13763238
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