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2 years ago

HELP PLEASE ASAP IM SO CONFUSED!!!!!!!!

Mathematics

1 answer:

liubo4ka [24]2 years ago

8 0

The slope-intercept form:

$y=mx+b$

m - slope

b - y-intercept → (0, b)

We have the points (-4, -6) and (2, 6). Substitute:

$m=\dfrac{6-(-6)}{2-(-4)}=\dfrac{12}{6}=2\\\\y=2x+b$

Put the coordinates of the point (2, 6) to the equation of a line:

$6=2(2)+b\\\\6=4+b\qquad|-4\\\\2=b\to b=2$

<h3>Answer: y = 2x + 2</h3>

You might be interested in

Simplify the following expression: Sqrt (-16) + sqrt(-25+5)

Studentka2010 [4]

Answer:

(4 + 2√5) i

Step-by-step explanation:

√(-16) + √(-25 + 5)

√(-16) + √(-20)

4i + 2i√5

(4 + 2√5) i

7 0

2 years ago

HELLOOOO HELP PLEASE

MA_775_DIABLO [31]

Answer:

$2*log(x)+log(y)$

Step-by-step explanation:

So, there are two logarithmic identities you're going to need to know.

Logarithm of a power:

$log_ba^c=c*log_ba$

So to provide a quick proof and intuition as to why this works, let's consider the following logarithm: $log_ba=x\implies b^x=a$

Now if we raise both sides to the power of c, we get the following equation: $(b^x)^c=a^c$

Using the exponential identity: $(x^a)^c=x^{a*c}$

We get the equation: $b^{xc}=a^c$

If we convert this back into logarithmic form we get: $log_ba^c=x*c$

Since x was the basic logarithm we started with, we substitute it back in, to get the equation: $log_ba^c=c*log_ba$

Now the second logarithmic property you need to know is

The Logarithm of a Product:

$log_b{ac}=log_ba+log_bc$

Now for a quick proof, let's just say: $x=log_ba\text{ and }y=log_bc$

Now rewriting them both in exponential form, we get the equations:

$b^x=a\\b^y=c$

We can multiply a * c, and since b^x = a, and b^y = c, we can substitute that in for a * c, to get the following equation:

$b^x*b^y=a*c$

Using the exponential identity: $x^{a}*x^b=x^{a+b}$ , we can rewrite the equation as:

$b^{x+y}=ac$

taking the logarithm of both sides, we get:

$log_bac=x+y$

Since x and y are just the logarithms we started with, we can substitute them back in to get: $log_bac=log_ba+log_bc$

Now let's use these identities to rewrite the equation you gave

$log(x^2y)$

As you can see, this is a log of products, so we can separate it into two logarithms (with the same base)

$log(x^2)+log(y)$

Now using the logarithm of a power to rewrite the log(x^2) we get:

$2*log(x)+log(y)$

3 0

1 year ago

Solve this <img src="https://tex.z-dn.net/?f=4%5Cleft%285x-2%5Cright%29%3D2%5Cleft%289x%2B3%5Cright%29" id="TexFormula1" ti

vampirchik [111]

Answer:

Solution of equation ( x ) = 7

Step-by-step explanation:

In this question we have given with an equation that is 4 ( 5x - 2 ) = 2 ( 9x + 3 ). And we are asked to solve this equation that means we have to find the value of x.

Solution : -

 $\quad \longrightarrow \: 4 ( 5x - 2 ) = 2 ( 9x + 3 )$ 

Step 1 : Removing parenthesis :

$\quad \longrightarrow \:20x - 8 = 18x + 6$

Step 2 : Adding 8 from both sides :

$\quad \longrightarrow \:20x - \cancel{ 8 }+ \cancel{8} = 18x + 6 + 8$

On further calculations we get :

$\quad \longrightarrow \:20x = 18x + 14$

Step 3 : Subtracting 18 from both sides :

$\quad \longrightarrow \:20x - 18x = \cancel{18x }+ 14 - \cancel{18}$

On further calculations we get :

$\quad \longrightarrow \:2x = 14$

Step 4 : Dividing with 2 on both sides :

$\quad \longrightarrow \: \frac{ \cancel{ 2}x}{ \cancel{2}} = \cancel{\frac{14}{2} }$

On further calculations we get :

$\quad \longrightarrow \: \blue{\boxed{ \frak{x = 7}}}$

Therefore, solution of this equation is 7 or we can say that value of this equation is 7 .

Verifying : -

We are verifying our answer by substituting value of x in given equation. So ,

4 ( 5x - 2 ) = 2 ( 9x + 3 )

4 [ 5 ( 7 ) - 2 ] = 2 [ 9 ( 7 ) + 3 ]

4 ( 35 - 2 ) = 2 ( 63 + 3 )

4 ( 33 ) = 2 ( 66 )

132 = 132

L.H.S = R.H.S

Hence, Verified.

Therefore, our value for x is correct .

<h2>#Keep Learning</h2>

4 0

1 year ago

Read 2 more answers

Help on these two plz help asp it's due tomorrow plz

zimovet [89]

Answer:

a = 615

Step-by-step explanation:

3 0

2 years ago

What is the value of x

Afina-wow [57]

Answer:

Step-by-step explanation:

Sin(30) = LJ/8sqrt(3)

Sin 30 = ½

LJ = 4sqrt(2)

LM = JM = x

x² + x² = (4sqrt(2))²

2x² = 32

x² = 16

x = 4

6 0

2 years ago