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Firdavs [7]
3 years ago
9

Select two netiquette guidelines. In a paragraph of no less than 125 words, explain why these guidelines make professional onlin

e communication more effective.
Computers and Technology
1 answer:
Paladinen [302]3 years ago
4 0

Respect others.

This means that it is important to make sure that your interactions with other internet users are based on respect for each other's resources. This includes time, bandwidth, and even emotions. Ensure that the information you are sharing is of value to the intended recipients and is sent in a timely manner. Treat other online users as you'd have them treat you.

Visualize your online conversations as you would real life conversations. Avoid being offensive and be accommodating of other peoples shortcomings. Also keep in mind who is part of the forum you are interacting with so as to use appropriate language. 



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We are building a word processor and we would like to implement a "reflow" functionality that full-justifies text.Given a maximu
adoni [48]

Answer:

The code is given below in Java with appropriate comments

Explanation:

Reflow is an function which helps you to justify your functionality

You need to input a string array and the max width and you will get the

output in a list(string).

public List<String> Reflow(String[] input, int width) {

   List<String> result = new ArrayList<String>();

 

   if(input==null || input.length==0){

       return result;

   }

 

 

   int count=0;

   int last=0;

   ArrayList<String> list = new ArrayList<String>();

   for(int i=0; i<input.length; i++){

       count = count + input[i].length();

 

       if(count+i-last>width){

           int wl = count-input[i].length();

           int sl = maxWidth-wl;

           int each = 1;

           int el = 0;

 

           if(i-last-1>0){

               each = sl/(i-last-1);

               el = sl%(i-last-1);

           }

 

           StringBuilder sb = new StringBuilder();

 

           for(int k=last; k<i-1; k++){

               sb.append(input[k]);

 

               int ce = 0;

               while(ce<each){

                   sb.append(" ");

                   ce++;

               }

 

               if(el>0){

                   sb.append(" ");

                   el--;

               }

           }

 

           sb.append(input[i-1]);//last input in the line

           //if only one word in this line, need to fill left with space

           while(sb.length()<width){

               sb.append(" ");

           }

 

           result.add(sb.toString());

 

           last = i;

           count=input[i].length();

       }

   }

 

   int lastLen = 0;

   StringBuilder sb = new StringBuilder();

 

   for(int i=last; i<input.length-1; i++){

       count = count+input[i].length();

       sb.append(input[i]+" ");

   }

 

   sb.append(input[input.length-1]);

   int d=0;

   while(sb.length()<maxWidth){

       sb.append(" ");

   }

   result.add(sb.toString());

 

   return result;

}

6 0
3 years ago
True or false? Resistors regulate and limit electrical current. A. True B. False
Vikki [24]
Hello! I believe the answer for this is "True"!
3 0
3 years ago
Read 2 more answers
Implementations <br> in c++ programming when finding lcm and gcd in c++​
vazorg [7]

Answer:

#include<iostream>

using namespace std;

int lcm(int m, int n) {

  int a;

  a = (m > n) ? m: n;

  while (true) {

     if (a % m == 0 && a % n == 0)

        return a;

        ++a;

  }

}

int gcd(int m, int n) {

  int r = 0, a, b;

  a = (m > n) ? m : n;

  b = (m < n) ? m : n;

  r = b;

  while (a % b != 0) {

     r = a % b;

     a = b;

     b = r;

  }

  return r;

}

int main(int argc, char **argv) {

  cout << "Enter the two numbers: ";

  int m, n;

  cin >> m >> n;

  cout << "The LCM of two numbers is: " << lcm(m, n) << endl;

  cout << "The GCD of two numbers is: " << gcd(m, n) << endl;  

  return 0;

}

Explanation:

7 0
3 years ago
Find out the names of at least 20 programming languages and their developers.
arlik [135]

Answer:

lala

Explanation:

6 0
3 years ago
Read 2 more answers
Explain how to implement two stacks in one array A[1..n] in such a way that neither stack overflows unless the total number elem
algol [13]

Answer:

Check explanation

Explanation:

Two stacks can make use of one array by utilizing various stack pointers that begins from different ends of an array. Looking at the array A[1...n], the first stack will drive elements that starts from position 1 as well as to move its' pointer to n.

The Second stack will begin at the n position and motion its' pointer to 1. The best likely divide is to offer each stack a half of an array. whenever any of two stacks transverse the half-point, an overflow can happen but for that overall number of elements, it must be n

5 0
3 years ago
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