The local minima of are (x, f(x)) = (-1.5, 0) and (7.980, 609.174)
<h3>How to determine the local minima?</h3>
The function is given as:
See attachment for the graph of the function f(x)
From the attached graph, we have the following minima:
Minimum = (-1.5, 0)
Minimum = (7.980, 609.174)
The above means that, the local minima are
(x, f(x)) = (-1.5, 0) and (7.980, 609.174)
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Answer:
6^10
Step-by-step explanation:
We know that a^ -b = 1/ a^b
So 1/ a^-b = a^b
1/6^-10 = 6^10
If the equation is passing trough the origin, it will be passing trough the point (0,0). We now for our problem that the equations is also passing trough the point (-4,3). So, our line is passing trough the points (0,0) and (-4,3). To write the equation in slope-intercept form, first, we need to find its slope . To do that we are going to use the slope formula: .
From our two points we can infer that , , , . Lets replace those values in the slope formula:
Now that we have our slope, we can use the slope-intercept formula:
We can conclude that the equation of the line passing trough the points (0,0) and (-4,3) is .
B.) S<span>ubstances that are made up of only one type of atom</span>
Answer:
c
Step-by-step explanation: