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Alexus [3.1K]
2 years ago
5

A 4. 9-mm-wide swimming pool is filled to the top. The bottom of the pool becomes completely shaded in the afternoon when the su

n is 20 ∘∘ above the horizon.
Mathematics
1 answer:
cestrela7 [59]2 years ago
6 0

The depth of the swimming pool that is filled to the top is; 4 m

<h3>Snell's Law</h3>

I have attached a schematic diagram showing this question.

The correct width of the pool is 4 meters. Thus; w = 4 m

Incident Angle; θ₁ = 20°

A right angle is 90° and so the angle θ₂ is calculated from;

θ₂ = 90° - θ₁

θ₂ = 90° - 20°

θ₂ = 70°

We can use snell's law formula to find θ₃.

Thus;

n₁sinθ₂ = n₂sinθ₃

where;

n₁ is refractive index of air = 1

n₂ is refractive index of water = 1.33

Thus;

1*sin 70 = 1.33*sin θ₃

sin θ₃ = (sin 70)/1.33

Solving this gives;

θ₃ = 44.95°

By usage of trigonometric ratios we can find the depth of the pool using;

w/d = tan θ₃

Thus;

d = w/(tan θ₃)

d = 4/(tan 44.95)

d ≈ 4 m

Read more about Snell's Law at; brainly.com/question/10112549

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Evaluate the triple integral_E x^6e^y dV where E is bounded by the parabolic cylinder z = 25 - y^2 and the planes z = 0, x = 5,
Nimfa-mama [501]

Nothing crazy here, just a matter of figuring out the limits of integration.

\displaystyle\iiint_Ex^6e^y\,\mathrm dV=\int_{-5}^5\int_{-5}^5\int_0^{25-y^2}x^6e^y\,\mathrm dz\,\mathrm dy\,\mathrm dx

=\displaystyle\int_{-5}^{-5}\int_{-5}^5x^6e^y(25-y^2)\,\mathrm dy\,\mathrm dx

=\displaystyle\left(\int_{-5}^5x^6\,\mathrm dx\right)\left(\int_{-5}^5e^y(25-y^2)\,\mathrm dy\right)=\boxed{\frac{625,000(3+2e^{10})}{7e^5}}

4 0
3 years ago
What's the surface area ratio &amp; the volume ratio??<br><br> please help me ASAP!!
Ulleksa [173]

Answer:

Step-by-step explanation:

Volumes of two spheres A and B = 648 cm³ and 1029 cm³

Things to remember:

1). Scale factor of two objects = \frac{r_1}{r_2} [r_1 and r_2 are the radii of two circles]

2). Area scale factor = \frac{(r_1)^2}{(r_2)^2}

3). Volume scale factor = \frac{(r_1)^3}{(r_2)^3}

Volume scale factor Or Volume ratio = \frac{V_A}{V_B}

                         \frac{(r_1)^3}{(r_2)^3}= \frac{648}{1029}

                         \frac{r_1}{r_2}=\sqrt[3]{\frac{648}{1029} }

                         \frac{r_1}{r_2}=\frac{6(\sqrt[3]{3})}{7(\sqrt[3]{3})}

                        \frac{r_1}{r_2}=\frac{6}{7}

Therefore, scale factor = \frac{r_1}{r_2}=\frac{6}{7}

                                      ≈ 6 : 7

Area scale factor Or area ratio = (\frac{r_1}{r_2})^2=(\frac{6}{7})^2

                                                   = \frac{36}{49}

                                                   ≈ 36 : 49

Volume scale factor or Volume ratio = \frac{648}{1029}

                                                             = \frac{216}{343}

                                                             ≈ 216 : 343

4 0
3 years ago
What I 80 multiplied by 2
tresset_1 [31]
80 multiplied by 2 is 160
6 0
3 years ago
A= 49 sq. in.<br><br> Find the value of x. If necessary, round to the nearest tenth.
BlackZzzverrR [31]

Answer:

9.90 inches

Step-by-step explanation:

Area of a triangle is equal to base times height divided by 2.

bh/2

Base and height is x.

xx/2=49

Solve for x.

x^2=49 \times 2

x^2=98

x=\sqrt{98}

x=9.899495

8 0
4 years ago
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WILL MARK BRAINLIEST! Which of the following is a discrete random variable? a) length of time you play in a baseball game b) len
Annette [7]

Answer:

d.which is number of candle's in a box

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3 years ago
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