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zysi [14]
3 years ago
11

Rewrite the following equation in slope intercept form 4x-5y=-20

Mathematics
1 answer:
pantera1 [17]3 years ago
4 0
Slope intercept form is y = mx + b.

Basically we need to get y by itself with no numbers attached.

4x - 5y = -20 subtract 4x from both sides
-5y = -4x - 20 divide each term on both sides by -5
y = (4/5)x + 4

hope this helps C:
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Sheila bought burgers and fries for her children and some friends. the burgers cost $2.05 each and the fries are $.85 each. she
jeyben [28]
Let's have B stand for burgers, and F stand for fries.
2.05B+0.85F=$19.10  - This equation is set equal to total price.
B+F=14  - This equation is set equal to total number of items.
Subtract the F in the bottom equation.
B=14-F
Put this in place of B in the first equation.
2.05(14-F)+0.85F=19.10
Make sure you distribute the 2.05 properly, over both the 14 and the F.
28.7 - 2.05F+0.85F=19.10
Collect like terms for the F values.
28.7 - 1.2F=19.10
Subtract 28.7 from both sides.
-1.2F=-9.6
Divide by -1.2 on both sides.
F=8
Put this value in place of F in either equation.
B+8=14
B=6
So F=8 and B=6.
4 0
3 years ago
What does 55 times 35
rosijanka [135]
55
×35

is 1925. You could use the estimation method if it doesn't require you to use the exact amount.
4 0
3 years ago
Read 2 more answers
Find a set of vectors {u⃗ ,v⃗ }{u→,v→} in r4r4 that spans the solution set of the equations {w−x+2y+4z5w+2x−y+3z==0,0. {w−x+2y+4
rusak2 [61]
Given

w-x+2y+4z=0 \\ 5w+2x-y+3z=0

We can rewrite it in matrix form as:

\left[\begin{array}{cccc}1&-1&2&4\\5&2&-1&3\\0&0&0&0\\0&0&0&0\end{array}\right]   \left[\begin{array}{c}w\\x\\y\\z\end{array}\right] =\left[\begin{array}{c}0\\0\\0\\0\end{array}\right] \\  \\ \left[\begin{array}{cccc}1&-1&2&4\\5&2&-1&3\\0&0&0&0\\0&0&0&0\end{array}\right|\left.\begin{array}{c}0\\0\\0\\0\end{array}\right]\ \ \ \ \ -5R_1+R_2\rightarrow R_2
\left[\begin{array}{cccc}1&-1&2&4\\0&7&-11&-17\\0&0&0&0\\0&0&0&0\end{array}\right|\left.\begin{array}{c}0\\0\\0\\0\end{array}\right]\ \ \ \ \  \frac{1}{7} R_2\rightarrow R_2 \\  \\ \left[\begin{array}{cccc}1&-1&2&4\\0&1&-\frac{11}{7}&-\frac{17}{7}\\0&0&0&0\\0&0&0&0\end{array}\right|\left.\begin{array}{c}0\\0\\0\\0\end{array}\right]\ \ \ \ \ R_1+R_2\rightarrow R_1
\\  \\ \left[\begin{array}{cccc}1&0&\frac{3}{7}&\frac{11}{7}\\0&1&-\frac{11}{7}&-\frac{17}{7}\\0&0&0&0\\0&0&0&0\end{array}\right|\left.\begin{array}{c}0\\0\\0\\0\end{array}\right] \\  \\ \Rightarrow w= -\frac{3}{7} y- \frac{11}{7} z \\ x=\frac{11}{7} y+ \frac{17}{7} z \\ y=free \\ z=free \\  \\ =y\left\ \textless \ -\frac{3}{7},\frac{11}{7}1,0\right\ \textgreater \ +z\left\ \textless \ - \frac{11}{7},\frac{17}{7},0,1\right\ \textgreater \

Thus, the solution set is a span of \{\left\ \textless \ -\frac{3}{7},\frac{11}{7}1,0\right\ \textgreater \ ,\left\ \textless \ - \frac{11}{7},\frac{17}{7},0,1\right\ \textgreater \ \}
7 0
3 years ago
What is the value of s?<br> ____ units
yulyashka [42]

Answer:

s = 17

Step-by-step explanation:

a^2+b^2=c^2

a=8, b=15, c=s

64+225=c^2

289 =c^2

c= 17

7 0
3 years ago
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Solve the equation and check the solution.
myrzilka [38]

A - 2 1/2 = 1 1/2

Solve for A by adding 2 1/2 to both sides:

A = 1 1/2 + 2 1/2

A = 4

The answer is c. A = 4

Check: 4 - 2 1/2 = 1 1/2

8 0
3 years ago
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