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Svetlanka [38]
3 years ago
15

Write 8867 to 2 significant figuresI can't remember how to do this. ​

Mathematics
1 answer:
diamong [38]3 years ago
8 0
The answer would be 8900
Reason: when you round to 2 significant figures you are trying to reduce the number to 2 digits and the rest will become 0 to indicate a place value
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August hosted two dinner parties for his friends. Twenty guests attended the first party, and thirty-three guests attended the s
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50%

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Does (3,7) make the inequality 2x+2y<20 true
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False

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Substitute x and y with the numbers in the coordinate pair.

Just as a recap-

3 is the x value

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I NEED THIS QUICKLY BCUZ ITS A TIMED TEST
GuDViN [60]

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Repeating decimals are rational, the square root of 1/8 is not rational, 19/5 is  rational, square root of 12 is not rational, the decimal is rational, square root of 49 is rational, and sqaure root of 4/25 is rational.

Step-by-step explanation:

Sorry if some of this is wrong :(

4 0
3 years ago
I had $13.00. My mom gave $10.00 my dad gave $30. My Aunt, My uncle and grandma gave me $100. I had another $7.00. How much did
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What is the following quotient? StartFraction 6 minus 3 (RootIndex 3 StartRoot 6 EndRoot) Over RootIndex 3 StartRoot 9 EndRoot E
Bezzdna [24]

Exponent properties help us to simplify the powers of expressions.  The quotient of the given expression \dfrac{6 - 3(\sqrt[3]{6})}{\sqrt[3]{9}} is (2∛3 - ∛18).

<h3>What are the basic exponent properties?</h3>

{a^m} \cdot {a^n} = a^{(m+n)}\\\\\dfrac{a^m}{a^n} = a^{(m-n)}\\\\\sqrt[m]{a^n} = a^{\frac{n}{m}}\\\\(a^m)^n = a^{m\times n}\\\\(m\times n)^a = m^a\times n^a\\\\

Given to us

\dfrac{6 - 3(\sqrt[3]{6})}{\sqrt[3]{9}}

We will solve the problem using the basic exponential properties,

\dfrac{6 - 3(\sqrt[3]{6})}{\sqrt[3]{9}}\\\\ = \dfrac{6}{\sqrt[3]{9}} - \dfrac{3(\sqrt[3]{6})}{\sqrt[3]{9}}\\\\ = (6\cdot 3^{-\frac{2}{3}}) - [3 \cdot (2 \cdot 3)^{-\frac{2}{3}}3^{-\frac{2}{3}}]\\\\= (2 \cdot 3 \cdot 3^{-\frac{2}{3}}) - [3 \cdot 2^{-\frac{2}{3}} \cdot 3^{-\frac{2}{3}}3^{-\frac{2}{3}}]\\\\

= [2 \cdot 3^{(1-\frac{2}{3})}] - [2^{\frac{1}{3}}\cdot 3^{(1+\frac{1}{3} - \frac{2}{3})}]\\\\=  [2 \cdot 3^{(\frac{1}{3})}] - [2^{\frac{1}{3}}\cdot 3^{(\frac{2}{3})}]\\\\= 2\sqrt[3]{3} - \sqrt[3]{2}\sqrt[3]{9}\\\\=2\sqrt[3]{3} - \sqrt[3]{18}

Hence, the quotient of the given expression \dfrac{6 - 3(\sqrt[3]{6})}{\sqrt[3]{9}} is (2∛3 - ∛18).

Learn more about Exponents:

brainly.com/question/5497425

4 0
2 years ago
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