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Akimi4 [234]
3 years ago
15

Solve the system using the elimination method.

Mathematics
1 answer:
spayn [35]3 years ago
6 0

Answer:

  (x, y, z) = (-22/13, 29/13, 6/13)

Step-by-step explanation:

Adding the first and second equations, we get ...

  (3x +2y -3z) +(7x -2y +5z) = (-2) +(-14)

  10x +2z = -16 . . . . collect terms

  5x + z = -8 . . . . . . divide by 2 . . . [eq4]

Adding twice the second equation to the third, we get ...

  2(7x -2y +5z) +(2x +4y +z) = 2(-14) +(6)

  16x +11z = -22 . . . . . . [eq5]

Now, we have two equations with the variable y eliminated. We can subtract [eq5] from 11 times [eq4] to eliminate z:

  11(5x +z) -(16x +11z) = 11(-8) -(-22)

  39x = -66

  x = -66/39 = -22/13

From [eq4], we can find z as ...

  z = -8 -5x = -8 -5(-22/13) = 6/13

And from the second equation, we get ...

  y = (1/2)(7x +5z +14) = (1/2)(7(-22/13) +5(6/13) +14) = 29/13

The solution is (x, y, z) = (-22/13, 29/13, 6/13).

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Jon is hitting baseballs. When he tosses the ball into the air, his hand is 5 feet above the ground. He hits the ball when it fa
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Answer:

Time  that will pass before Jon hits the ball is 0.5 seconds  

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Step-by-step explanation:

Step 1: To find out how much time passes before Jon hits the ball

The height he hits the ball when it falls is 4 feet

so,

4 =  - 16t^2 + 6t + 5

4 + 16t^2 - 6t - 5 = 0

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t =  \frac{-b \pm\sqrt{b^2-4ac}}{2a}

t =  \frac{-(-6) \pm\sqrt{(-6)^2-4(16)(-1)}}{2(16)}

t =  \frac{6 \pm\sqrt{36+64}}{32}

t =  \frac{6 \pm\sqrt{100}}{32}

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t =  \frac{16}{32}

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Step 2: To find the maximum height of the ball

Max height  will be reached at [\frac{-b}{2a}] sec

=\frac{-b}{2a}

\\ = \frac{-(-6)}{2\times16}\\

= \frac{6}{32}

Now the height at t= \frac{6}{32} is

16( \frac{6}{32})^2 - 6(  \frac{6}{32}) -1 = h

( \frac{6}{2})^2 -   \frac{36}{32} -1 = h

( 3)^2 -  1.125  -1 = h

9 -  1.125  -1 = h

6.875  =  h

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4 years ago
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