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Sergeeva-Olga [200]
3 years ago
10

Kristin spent $131 on shirts. Fancy shirts cost $28 and plain shirts cost $15. If she bought a total of 7 then how many of each

kind did she buy
Mathematics
1 answer:
Tpy6a [65]3 years ago
3 0
Hi there!!

First, Let plain shirts be x
Let fancy shirts be y 
x + y = 7
15x + 28y = 131 
Multiply first equation by 28 to eliminate y: 
28x + 28y = 196
<span>15x + 28y = 131 
</span>Subtracting the two equations:
13x = 65
<span>x = 5 </span>
Substituting x to get y:
x + y = 7
5 + y = 7
<span>y = 2 </span>
<span>Answer: 5 plain shirts and 2 fancy shirts
</span>
Hope this helps u!!
Have an amazing rest of ur day:)))
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The radius of a cone is increasing at a constant rate of 7 meters per minute, and the volume is decreasing at a rate of 236 cubi
storchak [24]

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Step-by-step explanation:

From the formula

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Differentiate the equation with respect to time t, such that

\frac{d}{dt} (V) = \frac{d}{dt} (\frac{1}{3}\pi r^{2}h)

\frac{dV}{dt} = \frac{1}{3}\pi \frac{d}{dt} (r^{2}h)

To differentiate the product,

Let r² = u, so that

\frac{dV}{dt} = \frac{1}{3}\pi \frac{d}{dt} (uh)

Then, using product rule

\frac{dV}{dt} = \frac{1}{3}\pi [u\frac{dh}{dt} + h\frac{du}{dt}]

Since u = r^{2}

Then, \frac{du}{dr} = 2r

Using the Chain's rule

\frac{du}{dt} = \frac{du}{dr} \times \frac{dr}{dt}

∴ \frac{dV}{dt} = \frac{1}{3}\pi [u\frac{dh}{dt} + h(\frac{du}{dr} \times \frac{dr}{dt})]

Then,

\frac{dV}{dt} = \frac{1}{3}\pi [r^{2} \frac{dh}{dt} + h(2r) \frac{dr}{dt}]

Now,

From the question

\frac{dr}{dt} = 7 m/min

\frac{dV}{dt} = 236 m^{3}/min

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We will determine the value of h, using

V = \frac{1}{3}\pi r^{2}h

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Answer:

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Step-by-step explanation:

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