Given
A tea that is 22% jasmine is blended with a tea that is 13% jasmine
Find out the how many pounds of the 22% jasmine tea are used to make 10lb of tea that is 19.3% jasmine.
To proof
Let us assume that the a tea that is 22% jasmine is blended = a
Let us assume that the a tea that is 13% jasmine is blended = b
Total amount of tea made = 10lb
the equation be
a + b = 10
as given
jasmine tea are used to make 10lb of tea that is 19.3% jasmine.
write 22% in the decimal form

= 0.22
write 13% in the decimal form

= 0.13
write 19.3% in the decimal form

= 0.193
than the equation be
0.22a + 0.13b = 0.193 × 10
on simplify
22a + 13b = 193
two equation becomes
22a + 13b = 193 and a + b = 10
multiply a + b = 10 by 13 and subtracted from the 22a + 13b = 193
we get
22a - 13a + 13b -13b = 193 - 130
9a = 63
a = 7lb
put this value in the a + b = 10
we get
7 + b = 10
b = 3lb
Therefore the 22% jasmine tea are used to make 10lb of tea that is 19.3% jasmine is 7 lb .
Hence proved
Answer:
x=16
Step-by-step explanation:
7x−2(3x−5)=26
Use the distributive property to multiply −2 by 3x−5.
7x−6x+10=26
Combine 7x and −6x to get x.
x+10=26
Subtract 10 from both sides.
x=26−10
Subtract 10 from 26 to get 16.
x=16
Graph if needed:
Angle CBA is congruent to angle GEF
Answer:
10.8 kilograms
Step-by-step explanation: