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ohaa [14]
3 years ago
8

Pleaseeeee help me!!!!!!!

Mathematics
1 answer:
Andrew [12]3 years ago
4 0

Answer:

118.3 m²

Step-by-step explanation:

The area (A) of a triangle is

A = \frac{1}{2} bh ( b is the base and h the perpendicular height )

Note the legs 13 and 18.2 are at right angles to each other, hence

A = 0.5 × 13 × 18.2 = 118.3

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Which number is NOT in the solution set of x − 9 &gt; 3?<br> A) 11 <br> B) 13 <br> C) 15 <br> D) 17
densk [106]

Answer:

A

Step-by-step explanation:

Given

x - 9 > 3 ( add 9 to both sides )

x > 12

13, 15 and 17 are all greater than 12

However, 11 is less than 12 and is not in the solution set → A

7 0
4 years ago
Read 2 more answers
Last season Ellen and Janet together won 32 tennis matches Ellen won 6 more than then Janet How many more matches did Ellen win
joja [24]

T = J + E

T = J + (J + 6)

T = 32

32 = 13 + (13 + 6)

32 = 13 + 19

32 = 32

Ellen won 19 matches.

8 0
3 years ago
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A game is played with a spinner on a circle, like the minute hand on a clock. The circle is marked evenly from 0 to 100, so, for
zheka24 [161]

Answer:

The probability is 1/2

Step-by-step explanation:

The time a person is given corresponds to a uniform distribution with values between 0 and 100. The mean of this distribution is 0+100/2 = 50 and the variance is (100-0)²/12 = 833.3.

When we take 100 players we are taking 100 independent samples from this same random variable. The mean sample, lets call it X, has equal mean but the variance is equal to the variance divided by the length of the sample, hence it is 833.3/100 = 8.333.

As a consecuence of the Central Limit Theorem, the mean sample (taken from independant identically distributed random variables) has distribution Normal with parameters μ = 50, σ= 8.333. We take the standarization of X, calling it W, whose distribution is Normal Standard, in other words

W = \frac{X - \mu}{\sigma} = \frac{X - 50}{8.333} \simeq N(0,1)

The values of the cummulative distribution of the Standard Normal distribution, lets denote it \phi , are tabulated and they can be found in the attached file, We want to know when X is above 50, we can solve that by using the standarization

P(X > 50) = P(\frac{X-50}{8.33} > \frac{50-50}{8.33}) = P(W > 0) = \phi(0) = 1/2

Download pdf
8 0
4 years ago
Please help, When do you need to approximate an irrational number with a rational value? Explain your understanding and give an
disa [49]

9514 1404 393

Answer:

  in any numerical computation; numerical values can only be rational numbers

Step-by-step explanation:

Any time a number is written down as a numerical value, it is a rational number. The numerical values we give to π or e or any root, logarithm, trig function, and polynomial solution are, of necessity, rational approximations to the true value. An "exact" value for an irrational number cannot be written down, so it must be approximated any time its numerical value is needed.

8 0
3 years ago
Arrange the geometric series from least to greatest based on the value of their sums.
son4ous [18]

Answer:

80 < 93 < 121 < 127

Step-by-step explanation:

For a geometric series,

\sum_{t=1}^{n}a(r)^{t-1}

Formula to be used,

Sum of t terms of a geometric series = \frac{a(r^t-1)}{r-1}

Here t = number of terms

a = first term

r = common ratio

1). \sum_{t=1}^{5}3(2)^{t-1}

   First term of this series 'a' = 3

   Common ratio 'r' = 2

   Number of terms 't' = 5

   Therefore, sum of 5 terms of the series = \frac{3(2^5-1)}{(2-1)}

                                                                      = 93

2). \sum_{t=1}^{7}(2)^{t-1}

   First term 'a' = 1

   Common ratio 'r' = 2

   Number of terms 't' = 7

   Sum of 7 terms of this series = \frac{1(2^7-1)}{(2-1)}

                                                    = 127

3). \sum_{t=1}^{5}(3)^{t-1}

    First term 'a' = 1

    Common ratio 'r' = 3

    Number of terms 't' = 5

   Therefore, sum of 5 terms = \frac{1(3^5-1)}{3-1}

                                                 = 121

4). \sum_{t=1}^{4}2(3)^{t-1}

    First term 'a' = 2

    Common ratio 'r' = 3

    Number of terms 't' = 4

    Therefore, sum of 4 terms of the series = \frac{2(3^4-1)}{3-1}

                                                                       = 80

    80 < 93 < 121 < 127 will be the answer.

4 0
3 years ago
Read 2 more answers
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