Answer:
32 5/8 (or 32 and 5/8)
Step-by-step explanation:
Okay, so this problem is asking for us to solve this problem with the substitution of a variable: x = -4. Before we fully solve this problem, we need to replace all of those x variables with -4 so that it is easier to solve.
-7 1/4(-4) + 3 5/8.
To make this problem even easier to solve, let's turn these mixed numbers into improper fractions. To do this, multiply the denominator by the whole number. Then add the numerator to this number. The new number that you just got is now your new numerator for this number.
-29/4(-4) + 3 5/8.
Repeat the last step to turn the other mixed number into an improper fraction.
-29/4(-4) + 29/8.
Now let's multiply that -4 by 29/4. Because a whole number technically has a denominator of 1, we can now set up the next part of our problem. (The symbol * means multiplication since we can't use x since it is already being used as a variable in this equation.)
(-29/4 * -4/1) + 29/8.
29 + 29/8.
Now to solve the rest of this problem, let's convert the whole number of 29 so that it has a denominator of 8. This is that these two numbers are addable.
<u>29</u> x <u>8</u> = <u>232</u>
1 x 8 = 8
Now these numbers are addable. So:
232/8 + 29/8 = 261/8 = 32 5/8.
I hope that this helps.
Answer:
6m^2-17m+12
Step-by-step explanation:
Carry out the binomial expansion in the numerator:
Then the 9⁴ terms cancel each other, so in the limit we have
Since <em>h</em> is approaching 0, that means <em>h</em> ≠ 0, so we can cancel the common factor of <em>h</em> in both numerator and denominator:
Then when <em>h</em> converges to 0, each remaining term containing <em>h</em> goes to 0, leaving you with
or choice C.
Alternatively, you can recognize the given limit as the derivative of <em>f(x)</em> at <em>x</em> = 9:
We have <em>f(x)</em> = <em>x</em> ⁴, so <em>f '(x)</em> = 4<em>x</em> ³, and evaluating this at <em>x</em> = 9 gives the same result, 2916.
Length of GH is also 11 meters
Answer:
Step-by-step explanation:
ok so i think you need 15g sait/7g yeast/29ml oil/428ml water
