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IrinaVladis [17]
3 years ago
13

Suppose the price and supply of strawberries are related by p= S(q)= 0.25q, where p is the pricw in ( in dollars) and q is the q

uantity supplied in (hundreds of quarts) of strawberries.
Find the quantity supplied at each price below.
a. $0 b. $2 c. $4.50
Mathematics
1 answer:
kipiarov [429]3 years ago
4 0
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Leyan bought 234 pounds of apples for $1.32 per pound, 112 pounds of peaches for $1.20 per pound, and some tomatoes, all from a
velikii [3]

Answer: See explanation

Step-by-step explanation:

I think your question isn't well written and that 234 was meant to be 2.34 and 112 was meant to be 1.12

Let the amount spent on tomatoes be x.

The information given in the question can then be used to form an equation as thus:

Apples + Peaches + Tomatoes = $9.63

(2.34 × $1.32) + (1.12 × $1.20) + x = $9.63

$3.0888 + $1.344 + x = $9.63

x = $9.63 - ($3.0888 + $1.344)

x = $9.63 - $4.4328

x = $5.1972

The amount spent on tomatoes will be $5.1972

8 0
2 years ago
Read 2 more answers
Can y’all help me please !
Leviafan [203]

no because she turned it only 90 degrees not 180.

180 would be a mirror reflection

6 0
2 years ago
HELP ME PLZZ, ASAP!!<br><br> In your own words explain what a Right Angle is.
anastassius [24]
A right angle is an angle at 90 degrees
5 0
2 years ago
Suppose that an airline uses a seat width of 16.5 in. Assume men have hip breadths that are normally distributed with a mean of
Alexxx [7]

Answer:

a) 0.018

b) 0            

Step-by-step explanation:

We are given the following information in the question:

Mean, μ =  14.4 in

Standard Deviation, σ = 1 in

We are given that the distribution of breadths is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

a) P(breadth will be greater than 16.5 in)

P(x > 16.5)

P( x > 16.5) = P( z > \displaystyle\frac{16.5 - 14.4}{1}) = P(z > 2.1)

= 1 - P(z \leq 2.1)

Calculation the value from standard normal z table, we have,  

P(x > 16.5) = 1 - 0.982 = 0.018 = 1.8\%

0.018 is the probability that if an individual man is randomly​ selected, his hip breadth will be greater than 16.5 in.

b) P( with 123 randomly selected​ men, these men have a mean hip breadth greater than 16.5 in)

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}  

P(x > 16.5)  

P( x > 16.5) = P( z > \displaystyle\frac{16.5-14.4}{\frac{1}{\sqrt{123}}}) = P(z > 23.29)  

= 1 - P(z \leq 23.29)

Calculation the value from standard normal z table, we have,  

P(x > 16.5) = 1 - 1 = 0

There is 0 probability that 123 randomly selected men have a mean hip breadth greater than 16.5 in

4 0
3 years ago
Find the exponential function that satisfies the given conditions:
Nady [450]

Answer:

f(t) = 66·0.995^t

Step-by-step explanation:

You can try t=0 and t=1 in each of the formulas to see which one gives values of 66 and 0.5% less than 66, or 65.67.

The first function has an initial value of 0.5, so is not correct.

The second function gives f(1) = 99, so is not correct.

The third function gives f(1) = 65.67, so is correct.

The fourth function gives f(1) = 66.33, so is not correct.

_____

You can realize that the multiplier will be 0.5% less than 100%, so will be 99.5% = 0.995. This number shows up only in the third selection.

4 0
3 years ago
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