2 8 −10−15÷3=2, start superscript, 8, end superscript, minus, 10, minus, 15, divided by, 3, equals
Sergio039 [100]
Answer:
241
Step-by-step explanation:
Given the equation to evaluate :
2^8 −10−15÷3
2^8 = 256
256 - 10 - 15 ÷ 3
From BODMAS principle, we evaluate the divison before subtraction :
-15 ÷ 3 = - 5
256 - 10 -5
256 - 15
= 241
Answer:

Explanation:
Since
is a diameter, arc 
Given that
is a subtended central angle by two diameters,
.
Using the rule of arcs,
→



Answer:
27
Step-by-step explanation:
The equation is a onestep equation, so in order to find the variable, follow these steps:
d - 4 = 23
In order to isolate the variable or get the variable by itself, you need to get rid of the constants around it or the numbers without a variable. In order to do that for this equation, you'll need to do the inverse of subtracting 4, which would be adding four to both sides.
Adding 4 to positive 23 will give you the answer of 27;
d = 27
Therefore, the variable d equals 27
Hope this helps!
Answer:
For the perfect square trinomial (quadratic) i.e.
, the constant term (last term) is positive.
Step-by-step explanation:
"Perfect square trinomials" are termed as the quadratics that are the outcomes of squaring binomials.
For example:





Therefore, for the perfect square trinomial (quadratic) i.e.
, the constant term (last term) is positive.