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Pavel [41]
3 years ago
14

What is a postitve root of the equation x^2+5x=150

Mathematics
2 answers:
Hunter-Best [27]3 years ago
6 0
x^2 + 5x =150

x^2 + 5x -150 = 0

(x-10)(x+15)= 0

Two roots, x=10 and x=-15

Positive root: x=10

Check:  10^2 + 5(10) = 150, good




Sladkaya [172]3 years ago
3 0
To solve this equation, we can solve it like it is a quadratic (because it is). To solve it like it's a quadratic, we need to get one side equal to 0. We can do that by subtracting 150 from each side. That gives us x² + 5x -150 = 0. Now, we can factor the equation. Factoring it gives us (x-10)(x+15) = 0. Now, using the zero-product property, we can conclude the the roots for this equation are x = 10, -15. But, since the question is only asking us for the positive root, the answer is x = 10. 
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