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3 years ago

Simplify: square root 8i^2

Mathematics

1 answer:

Vesna [10]3 years ago

8 0

Answer: The answer would be to simplify the radical by breaking the radicand up into a product of known factors, assuming positive real numbers.

2i√2

So according to me the answer should be 2i√2 .

* Hopefully this helps: )

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Sovle the following inequality -3m + 18 < 30

denis-greek [22]

Answer:

m>-4

Step-by-step explanation: First subtract 18 from both sides, then simplify 30-18, which equals 12. Divide both sides by -3, and flip your sign.

7 0

3 years ago

Find the equation of the line with the given slope and containing the given point. slope -7/10; through (-8,0)

Kisachek [45]

Answer:

$y = -\frac{7}{10}(x + 8)$

Step-by-step explanation:

To write the equation of a line, substitute m = -7/10 and the point (-8,0) into the point slope formula.

$y - y_1=m(x-x_1)\\y - 0 = -\frac{7}{10}(x --8)\\y = -\frac{7}{10}(x + 8)$

5 0

3 years ago

(A)using geometry vocabulary, describe a sequence of transformations that maps figure P (-1,2)(-1,4) (-4,2) (-4,4) onto figure Q

andrey2020 [161]

Before we proceed on determining the transformation happening on this problem, it's better to see first the location of the figure by drawing it in a cartesian coordinate plane. We have

If we observe the figures and the coordinates of the plot, we can see that there is a difference of 1 on the x coordinates of P and y coordinates of Q. Therefore, the first transformation that we consider here is the movement of figure P by 1 unit to the left. We have

$\begin{gathered} P_1=(-1-1,2_{})=(-2,2) \\ P_2=(-1-1,4)=(-2,4) \\ P_3=(-4-1,2)=(-5,2) \\ P_4=(-4-1,4)=(-5,4) \end{gathered}$

This transformation changes the location of figure P into

The next transformation will be the rotation of the red dotted figure on the figure above by 90 degrees counterclockwise. With this transformation, the coordinates will transform as

$P_{ccw,90}=(-y,x)$

Hence, for the rotation, we have the new coordinates.

$\begin{gathered} P_1^{\prime}=(-2,-2) \\ P_2^{\prime}=(-4,-2) \\ P_3^{\prime}=(-2,-5) \\ P_4^{\prime}=(-4,-5) \end{gathered}$

The transformed image, which is represented as NMPO, will now be at

For the last transformation, we will be reflecting the figure NMPO over the y axis. This changes the coordinates as

$P_{\text{rotation,y}-\text{axis}}=(-x,y)$

We now have the new coordinates:

$\begin{gathered} P^{\doubleprime}_1=(2,-2)=Q_1_{}_{} \\ P_2^{\doubleprime}=(4,-2)=Q_3 \\ P_3^{\doubleprime}=(2,-5)=Q_2 \\ P_4^{\doubleprime}_{}=(4,-5)=Q_4_{} \end{gathered}$

As you can see, they have the same coordinates as figure Q.

The mapping rules for the sequence described above are as follows:

First transformation (moving one unit to the left (x-1,y))

$\begin{gathered} P_1(-1,2)\rightarrow P_1(-1-1,2)\rightarrow P_1(-2,2) \\ P_2(-1,4)\rightarrow P_1(-1-1,4)\rightarrow P_2(-2,4) \\ P_3(-4,2)\rightarrow P_1(-4-1,2)\rightarrow P_3(-5,2) \\ P_4(-4,4)\rightarrow P_1(-4-1,4)\rightarrow P_4(-5,4) \end{gathered}$

Second transformation (rotation counter clockwise (-y,x))

$\begin{gathered} P_1(-2,2)\rightarrow P^{\prime}_1(-2,-2)_{} \\ P_2(-2,4)\rightarrow P^{\prime}_2(-4,-2) \\ P_3(-5,2)\rightarrow P^{\prime}_3(-2,-5)_{} \\ P_4(-5,4)\rightarrow P^{\prime}_4(-4,-5)_{} \end{gathered}$

Third Transformation (reflection over y-axis (-x,y))

$\begin{gathered} P^{\prime}_1(-2,-2)\rightarrow P^{\doubleprime}_1(-(-2),-2)\rightarrow P^{\doubleprime}_1=(2,-2)=Q_1 \\ P^{\prime}_2(-4,-2)\rightarrow P^{\doubleprime}_1(-(-4),-2)\rightarrow P^{\doubleprime}_1=(4,-2)=Q_3 \\ P^{\prime}_3(-2,-5)\rightarrow P^{\doubleprime}_1(-(-2),-5)\rightarrow P^{\doubleprime}_1=(2,-5)=Q_2 \\ P^{\prime}_4(-4,-5)\rightarrow P^{\doubleprime}_1(-(-4),-5)\rightarrow P^{\doubleprime}_1=(4,-5)=Q_4 \end{gathered}$

7 0

1 year ago

What is the product in lowest terms? -5/12*8/13

FrozenT [24]

-5/12*8/13 to the lowest terms which equal -10/39.

8 0

3 years ago

How many possible numbers of solutions are there to the system of equations?

storchak [24]

Explanation:

Assuming a system of linear equations:

If the equations have the same slope, there are no possible solutions. Lines with the same slope run parallel and never intersect. Without an intersection, there is no solution. The solution is the point of intersection of graphs.

If the equations are equivalent, there are an infinite number of solutions. Equations can be equivalent in many ways. If one equation is rearranged to isolate one of its variables, the new equations looks different but it is equivalent. (Most commonly, two equivalent equations are in different forms, like standard, slope-intercept or point-intercept). If an equation has all of its terms multiplied or divided by the same number, the new equation is equivalent.

In any other case, there is only one solution.

3 0

3 years ago