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BARSIC [14]
3 years ago
9

Help me plz i need help on math i will give THANKS

Mathematics
1 answer:
atroni [7]3 years ago
8 0
The answer is for your paper is 21
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A wise man once said, "400 reduced by 3 times my age is 208" What is the mans age
yanalaym [24]

Answer:

96

Step-by-step

explanation:

400−2x=208. 400−208=2x. 192=2x. x=96

6 0
3 years ago
Read 2 more answers
A website is offering a promotion, during which customers can buy up to 100 photos for a flat fee. The cost per photo varies inv
Alecsey [184]
The complete question in the attached figure

we have that
 for c=5 and n=20------------> n*c=20*5=100
 for c=2.5 and n=40------------> n*c=40*2.5=100
 for c=2 and n=50------------> n*c=50*2=100
 for c=1.25 and n=80------------> n*c=80*1.25=100

therefore
<span>the function that models the data is n*c=100
</span>
the answer is nc=100





6 0
3 years ago
If the equation y = 3x + 2 is changed to y = -3x + 2, how will the graph of the line change?
MrRissso [65]
The line will flip across the y-axis.
7 0
3 years ago
how does kasey situation change . the function? write a new function k(t) to represent kaseys account balance to any year t
rjkz [21]

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6 0
3 years ago
Simplify (-3c^-3w^5)^3<br> A -9w^8<br> B. -27cw^8<br> C. w^15/27c^9<br> D.-27w^15/c^9
kenny6666 [7]

Answer:

\large\boxed{D.\ \dfrac{-27w^{15}}{c^9}}

Step-by-step explanation:

(-3c^{-3}w^5)^3\qquad\text{use}\ (ab)^n=a^nb^n\\\\=(-3)^3(c^{-3})^3(w^5)^3\qquad\text{use}\ (a^n)^m=a^{nm}\\\\=-27c^{-3\cdot3}w^{5\cdot3}=-27c^{-9}w^{15}\qquad\text{use}\ a^{-n}=\dfrac{1}{a^n}\\\\=-27\left(\dfrac{1}{c^9}\right)w^{15}=\dfrac{-27w^{15}}{c^9}

4 0
3 years ago
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