If you follow PEMDAS, multiplication would be first, so 3*2 is 6, then it's addition.
So 3*2=6 and 8*-16 is -128, then you add them both.
So 6+(-128) is equals to -122. YOU'RE WELCOME :D

7 0

4 years ago

Consider functions f and g.1 + 12f(1) = 12 + 4. – 12for * # 2 and 7 -64.2 – 16. + 1641 +48for a # -12 Which expression is equal

lisabon 2012 [21]

Given the following functions below,

$\begin{gathered} f(x)=\frac{x+12}{x^2+4x-12}\text{ and} \\ g(x)=\frac{4x^2-16x+16}{4x+48} \end{gathered}$

Factorising the denominators of both functions,

Factorising the denominator of f(x),

$\begin{gathered} f(x)=\frac{x+12}{x^2+4x-12}=\frac{x+12}{x^2+6x-2x-12}=\frac{x+12}{x(x+6)-2(x+6)}=\frac{x+12}{(x-2)(x+6)} \\ f(x)=\frac{x+12}{(x-2)(x+6)} \end{gathered}$

Factorising the denominator of g(x),

$\begin{gathered} g(x)=\frac{4x^2-16x+16}{4x+48}=\frac{4(x^2-4x+4)}{4(x+12)} \\ \text{Cancel out 4 from both numerator and denominator} \\ g(x)=\frac{x^2-4x+4}{x+12}=\frac{x^2-2x-2x+4}{x+12}=\frac{x(x-2)-2(x-2)}{x+12}=\frac{(x-2)^2}{x+12} \\ g(x)=\frac{(x-2)^2}{x+12} \end{gathered}$

Multiplying both functions,

$undefined$

4 0

1 year ago

Answer the question above

joja [24]

(5,1) Is Point Form.

Via; Equation Form:

x = 5,y = 1

I used Solve the System of Equations to solve

7 0

3 years ago

Damon is locked out of his house. The only open window is on the second floor. Which is 12 feet above the ground. He needs to bo

Sonja [21]

Use the Pythagorean theorem
A^2+b^2=c^2
12^2+5^2=c^2
144+25=c^2
169=c^2
13=c
13 foot ladder

6 0

3 years ago