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olganol [36]
3 years ago
15

What is the answer and could you explain

Mathematics
2 answers:
kotegsom [21]3 years ago
7 0
D: 16: Since penny has 2 sides there's a 50/50 chance it could land on heads or tails.

pishuonlain [190]3 years ago
3 0
16 different combinations. There are 8 sections on the spinner and 2 sides on a coin. 8 combinations for heads and 8 for tails, which equals 16.

I hope this helps. If it does, please mark it as Brainliest
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12+98=<br> really confused on this one
kipiarov [429]

Answer:

12+98=110

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
2. The number of atoms of a particular chemical element is modelled by
____ [38]

9514 1404 393

Answer:

  a) 600

  b) see below

  c) 1.26 hours

Step-by-step explanation:

a) The value of y when x=0 is the coefficient of the exponential term:

  y = 600·3^(-0) = 600·1 = 600

There were 600 atoms to start.

__

b) see attached for a graph

__

c) The graph shows 150 atoms at t = 1.26, about 1.26 hours after the start of time counting.

If you want to find that value algebraically, substitute for y and solve for x. Logarithms are involved.

  150 = 600·3^(-x)

  150/600 = 3^(-x)

  log(1/4) = -x·log(3)

  x = -log(1/4)/log(3) = log(4)/log(3) ≈ 1.2618595

After about 1.26 hours, there were 150 atoms.

6 0
3 years ago
HURRY!
yuradex [85]
-3 x + 1 > y
1/2x -1 (less than or equal to) y

See photo


3 0
2 years ago
Which ratio represents the tangent of an angle?
azamat

Answer:

option d.opposite / adjacent

Step-by-step explanation:

opposite /adjacent ratio represents the tangent of an angle .

hope it is helpful to you ☺️

3 0
2 years ago
Read 2 more answers
The half-life of cesium-137 is 30 years. Suppose we have a
VMariaS [17]
(a) If y(t) is the mass (in mg) remaining after t years, then y(t) = y(0) e^{kt}=100e^{kt}.

y(30) = 100 e^{30k} = \frac{1}{2}(100) \implies e^{30k} = \frac{1}{2} \implies k = -(\ln 2) /30 \implies \\ \\&#10;y(t) = 100e^{-(\ln 2)t/30} = 100 \cdot 2^{-t/30}

(b) y(100) = 100 \cdot 2^{-100/30} \approx \text{9.92 mg}

(c)
100 e^{- (\ln 2)t/30} = 1\ \implies\ -(\ln 2) t / 30 = \ln \frac{1}{100}\ \implies\ \\ \\&#10;t = -30 \frac{\ln 0.01}{\ln 2} \approx \text{199.3 years}
 
3 0
3 years ago
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