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3 years ago

In right ∆PQR, P and Q are acute angles, and cos P is 3/5. What is sin Q? Answers: 4/5 3/5 2/5 3/4

Mathematics

1 answer:

Andrews [41]3 years ago

4 0

$Look\ at\ the\ picture.\\\\cos\alpha=\frac{3}{5};\ cos\alpha=\frac{b}{c}\\\\sin\beta=\frac{b}{c}=cos\alpha\\\\therefore\\\\sin\beta=\frac{3}{5}\\\\Answer:\huge\boxed{\frac{3}{5}}$

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Which description is paired with its correct expression?

Snowcat [4.5K]

Answer:

Step-by-step explanation:

We can write our unknown number like x

four less than the quotient of a number cubed and seven, increased by three

$4-\frac{x^3}{7}+3$

five times the difference of a number squared and six

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$9+\frac{6}{x^3}-4$

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3 years ago

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Which translation rule describes the translation that is 6 units to the left and 5 units down?

Ronch [10]

There both going in the negative direction so I would assume the second one were they both are negative

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3 years ago

What is the equation of a line, in point- slope form, that passes through (5, −3)(5, −3) and has a slope of 2323 ? y+5=23(x−3)y+

Marta_Voda [28]

Youyou havehave aa seriousserious doubledouble pastepaste problemproblem

the equation of the line that passes through the point (x1,y1) and has a slope of m is
y-y1=m(x-x1)
given

the point is (5,-3) and the slope is 23 (or it could be 2/3)
x1=5
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3 years ago

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Please help!!!!!>>>>>>

brilliants [131]

I believe it would be the third one, with the open circle on -2 going towards the right

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3 years ago

A cylinder shaped water pitcher has a radius of 5 inches and a height of 12.5 inches find the surface area of the pitcher

VladimirAG [237]

<h2>Question:-</h2>

A cylinder shaped water pitcher has a radius of 5 inches and a height of 12.5 inches. Find the surface area of the pitcher.

<h2>Answer:-</h2>

<h3>Given:-</h3>

$\bullet$ Radius (r) of a cylinder shaped water pitcher = 5 inches.

$\bullet$ Height (h) of a cylinder shaped water pitcher = 12.5 inches.

The surface area of the pitcher.

<h2>Solution:-</h2>

We know,

Formula of Surface area of a cylinder is 2πr(r + h) sq. units.

So,

Surface area of the pitcher = 2 × 3.14 × 5(5 + 12.5)

Surface area of the pitcher = 31.4 × 17.5

Surface area of the pitcher = 549.5 in²

$\therefore$ The surface area of the pitcher is 549.5 in².

Hence, the option (C) 549.5 in² is correct. [Answer]

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3 years ago