2x² (6x³+3x+4) is your answer
hope this helps
Using the Normal distribution, it is found that 0.0359 = 3.59% of US women have a height greater than 69.5 inches.
In a <em>normal distribution</em> with mean
and standard deviation
, the z-score of a measure X is given by:
- It measures how many standard deviations the measure is from the mean.
- After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
US women’s heights are normally distributed with mean 65 inches and standard deviation 2.5 inches, hence
.
The proportion of US women that have a height greater than 69.5 inches is <u>1 subtracted by the p-value of Z when X = 69.5</u>, hence:



has a p-value of 0.9641.
1 - 0.9641 = 0.0359
0.0359 = 3.59% of US women have a height greater than 69.5 inches.
You can learn more about the Normal distribution at brainly.com/question/24663213
A a b...............................
Since we know that ratio of AB : AC is 1 : √2, then we can more or less use those values for the sides, check the picture below.
so we're really looking for tan(2A). Let's bear in mind that tan²(θ) is just another way to write [ tan(θ) ]².
Step-by-step explanation:
44-9=35
35-9=26
26-9=17
17-9=8