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serious [3.7K]
3 years ago
12

Solve for x: −4|x + 5| = −16

Mathematics
2 answers:
san4es73 [151]3 years ago
7 0

-4 |x+5| = -16

Divide both sides by -4

|x+5| = 4

x = -1

wel3 years ago
7 0

-4|x + 5| = -16\\\\|x+5|=4\\\\x+5=4 \vee x+5=-4\\\\x=-1 \vee x=-9

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What equation represents the model shown below?
g100num [7]

Given:

The algebra tiles of an equation.

To find:

The equation represented by the given model.

Solution:

On the left side of the model we have 4 tiles of (-x) and 3 tiles of (-1). So,

LHS=(-x)+(-x)+(-x)+(-x)+(-1)+(-1)+(-1)

LHS=-4x+(-3)

LHS=-4x-3

On the right side of the model we have 8 tiles of (-1). So,

RHS=(-1)+(-1)+(-1)+(-1)+(-1)+(-1)+(-1)+(-1)

RHS=-8

Now, equate the LHS and RHS to get the equation.

-4x-3=-8

Therefore, the equation for the given model is -4x-3=-8.

7 0
2 years ago
Whats the answer to -20=-4x-6x
Marina86 [1]
2 Would be the answer.


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7 0
3 years ago
Use the divisibility rules to determine which of the following numbers 504 is divisible by.
Reika [66]

Answer:

504 is divisible by 2, 3, and 7. It is not divisble by 5 or 11

Step-by-step explanation:

C'mon. Use a calcultor.

3 0
3 years ago
A research report says that t(63) = 1.99; p = .03. From that information, can you reject the null hypothesis with 95% confidence
Leona [35]

Answer:

Yes, I can reject the null hypothesis with 95% confidence.

Step-by-step explanation:

Critical value t(63) = 1.99

p-value = 0.03

Confidence level (C) = 95% = 0.95

Significance level = 1 - C = 1 - 0.95 = 0.05

Conclusion:

Reject the null hypothesis because the p-value 0.03 is less than the significance level 0.05.

4 0
2 years ago
Read 2 more answers
Please help with algebra problem
kumpel [21]
Number of weekend minutes used: x
Number of weekday minutes used: y

This month Nick was billed for 643 minutes:
(1) x+y=643

The charge for these minutes was $35.44
Telephone company charges $0.04 per minute for weekend calls (x)
and $0.08 per minute for calls made on weekdays (y)
(2) 0.04x+0.08y=35.44

We have a system of 2 equations and 2 unkowns:
(1) x+y=643
(2) 0.04x+0.08y=35.44

Using the method of substitution
Isolating x from the first equation:
(1) x+y-y=643-y
(3) x=643-y

Replacing x by 643-y in the second equation
(2) 0.04x+0.08y=35.44
0.04(643-y)+0.08y=35.44
25.72-0.04y+0.08y=35.44
0.04y+25.72=35.44

Solving for y:
0.04y+25.72-25.72=35.44-25.72
0.04y=9.72

Dividing both sides of the equation by 0.04:
0.04y/0.04=9.72/0.04
y=243

Replacing y by 243 in the equation (3)
(3) x=643-y
x=643-243
x=400

Answers:
The number of weekends minutes used was 400
The number of weekdays minutes used was 243
6 0
3 years ago
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