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gladu [14]
4 years ago
13

Polypeptides are synthesized from amino acid building blocks. The condensation reaction between the growing polypeptide chain an

d the next amino acid to be added involves the loss of ________________.
A. a water molecule.
B. an amino group.
C. a carbon atom.
D. a carboxylic acid group.

Chemistry
1 answer:
Naya [18.7K]4 years ago
5 0

Answer:

A) a water molecule.

Explanation:

During the condensation of amino acids to form polypeptide, the carboxylic group of one amino acid reacts with amino group of another amino acid. This leads to formation of amid linkage.

The reaction is shown in the figure.

As shown, there is removal of water molecule during formation of polypeptide.

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Units used in gas for pressure
Naya [18.7K]

Answer:

kilopascal, torr, and atmosphere

Explanation:

7 0
3 years ago
How many milliliters (mL) are in 0.847 liters (L)
alex41 [277]

Answer:

847 mL

Explanation:

Step 1: Find conversion

1 L = 1000 mL

Step 2: Use Dimensional Analysis

0.847 \hspace{2} L(\frac{1000 \hspace{2} mL}{1 \hspace{2} L} )

<em>We see that Liters and Liters cancel out, so we simply multiply.</em>

847 mL

7 0
3 years ago
1. Which statement describes the charge and location of an electron in an atom? A) An electron has a positive charge and is loca
damaskus [11]

Answer: option c an electron has a negative charge and is located outside the nucleus revolving in circular path

7 0
3 years ago
What is the empirical formula of a hydrocarbon if complete combustion or 2.900 mg of the hydrocarbon produced 9.803 mg of CO2 an
kow [346]

Answer:

The empirical formula of the hydrocarbon is CH.

Explanation:

The following data were obtained from the question:

Mass of hydrocarbon = 2.9 mg

Mass of CO2 = 9.803 mg

Mass of H2O = 2.006 mg

Next, we shall determine the mass of carbon (C) and hydrogen (H) in the compound since hydrocarbon contains carbon and hydrogen only.

This is illustrated below:

Molar mass of CO2 = 12 + (16x2) = 12 + 32 = 44 g/mol

Mass of CO2 = 9.803 mg

Mass of C in the compound =?

Mass of C in the compound =

12/44 x 9.803

= 2.674 mg

Molar mass of H2O = (2x1) + 16 = 2 + 16 = 18 g/mol

Mass of H2O = 2.006 mg

Mass of H in the compound =

2/18 x 2.006

= 0.223 mg

Finally, we shall determine the empirical formula of the hydrocarbon as follow:

Carbon (C) = 2.674 mg

Hydrogen (H) = 0.223 mg

Divide by their molar mass

C = 2.674 /12 = 0.223

H = 0.223 / 1 = 0.223

Divide both side by the the smallest

C = 0.223/0.223 = 1

H = 0.223/0.223 = 1

Therefore, the empirical formula of the hydrocarbon is CH.

5 0
3 years ago
If the carbon atom of each of the incoming CO2 molecules is labeled with a radioactive isotope of carbon, which organic molecule
DIA [1.3K]

Answer:

B, C, D, and E

Explanation:

Hope this helps let know if does if not sorry :)

5 0
2 years ago
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