If I initially have a gas at a pressure of 12 kPa, a volume of 23 liters, and a temperature of 200 K, and then I raise the press
1 answer:
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Answer:
option D is correct
D. This solution is a good buffer.
Explanation:
TRIS (HOCH)
CNH
if TRIS is react with HCL it will form salt
(HOCH)
CNH
+ HCL ⇆ (HOCH
)
NH
CL
Let the reference volume is 100
Mole of TRIS is = 100 × 0.2 = 20
Mole of HCL is = 100 × 0.1 = 10
In the reaction all of the HCL will Consumed,10 moles of the salt will form
and 10 mole of TRIS will left
hence , Final product will be salt +TRIS(9 base)
H = Pk + log (base/ acid)
8.3 + log(10/10)
8.3
The given question is incomplete. The complete question is:What is the relative atomic mass of a hypothetical element that consists isotopes in the indicated natural abundances.
Isotope mass amu Relative abundance
1 77.9 14.4
2 81.9 14.3
3 85.9 71.3
Express your answer to three significant figures and include the appropriate units.
Answer: 84.2 amu
Explanation:
Mass of isotope 1 = 77.9
% abundance of isotope 1 = 14.4% =
Mass of isotope 2 = 81.9
% abundance of isotope 2 = 14.3% =
Mass of isotope 3 = 85.9
% abundance of isotope 2 = 71.3% =
Formula used for average atomic mass of an element :
Therefore, the average atomic mass of a hypothetical element that consists isotopes in the indicated natural abundances is 84.2 amu