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3 years ago

6

A 220.0 mL sample of helium gas is in a cylinder with a movable piston at 105 kPa and 275 K. The piston is

1 answer:

Lemur [1.5K]3 years ago

5 0

Answer:

Explanation:

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When two substances react to form products, the reactant which is used up is called the ____.

Maksim231197 [3]

The reactant being used up is called limiting reagent as it limits the total amount of product produced.

if 4 units of HCL gives 2 units of Cl therefore
4:2
0.98:x
x=(0.98*2) /4
x=0.49L

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4 years ago

What happens when two hydrogen atoms enter the ETS as part of either NADH or FADH2? Two hydrogen and one oxygen react to form a

gtnhenbr [62]

I think the correct answer from the choices listed above is the second option. When two hydrogen atoms enter the ETS as part of either NADH or FADH2, the two hydrogen atoms are split into two H+ and two electrons. Hope this answers the questions.

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3 years ago

Read 2 more answers

A solution contains 3.1 mM Zn(NO3)2 and 4.2 mM Ca(NO3)2. The p-function for Zn2+ is _____, and the p-function for NO3- is _____.

seropon [69]

<u>Answer:</u> The p-function of $Zn^{2+}$ and $NO_3^{-}$ ions are 2.51 and 2.14 respectively.

<u>Explanation:</u>

p-function is defined as the negative logarithm of any concentration.

We are given:

Millimolar concentration of zinc nitrate = 3.1 mM

Millimolar concentration of calcium nitrate = 4.2 mM

Converting this into molar concentration, we use the conversion factor:

1 M = 1000 mM

Concentration of zinc nitrate = 0.0031 M = 0.0031 mol/L

1 mole of zinc nitrate produces 1 mole of zinc ions and 2 moles of nitrate ions

Concentration of zinc ions = 0.0031 M

Concentration of nitrate ions in zinc nitrate, $M_1=(2\times 0.0031)=0.0062M$

Concentration of calcium nitrate = 0.0042 M = 0.0042 mol/L

1 mole of calcium nitrate produces 1 mole of calcium ions and 2 moles of nitrate ions

Concentration of calcium ions = 0.0042 M

Concentration of nitrate ions in calcium nitrate, $M_2=(2\times 0.0042)=0.0084M$

To calculate the concentration of nitrate ions in the solution, we use the equation:

$M=\frac{M_1V_1+M_2V_2}{V_1+V_2}$

Putting values in above equation, we get:

$M=\frac{(0.0062\times 1)+(0.0084\times 1)}{1+1}\\\\M=0.0073M$

Calculating the p-function of zinc ions and nitrate ions in the solution:

<u>For zinc ions:</u>

$\text{p-function of }Zn^{2+}\text{ ions}=-\log[Zn^{2+}]$

$\text{p-function of }Zn^{2+}\text{ ions}=-\log(0.0031)\\\\\text{p-function of }Zn^{2+}\text{ ions}=2.51$

<u>For nitrate ions:</u>

$\text{p-function of }NO_3^{-}\text{ ions}=-\log[NO_3^{-}]$

$\text{p-function of }NO_3^{-}\text{ ions}=-\log(0.0073)\\\\\text{p-function of }NO_3^{-}\text{ ions}=2.14$

Hence, the p-function of $Zn^{2+}$ and $NO_3^{-}$ ions are 2.51 and 2.14 respectively.

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3 years ago

7.no . <br> with steps please anyone <br> no spam

gulaghasi [49]

Given mass=1.3g
Atomic mass=65u

Molar mass=65g/mol

Now

$\boxed{\sf No\:of\:moles=\dfrac{Given\:Mass}{Molar\:Mass}}$

$\\ \rm\longmapsto No\:of\;Moles=\dfrac{1.3}{65}=0.02mol$

6 0

3 years ago

***URGENT PLEASE**** Select all of the bases listed *

Masteriza [31]

Answer:

NaOH (a strong base)

Ammonia ( weak base )

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3 years ago