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3 years ago

I had 3 apples I eat two how many I had left

Mathematics

2 answers:

musickatia [10]3 years ago

5 0

Had or have? You had 3 now you have 3 just 2 are eaten.

Evgesh-ka [11]3 years ago

4 0

If you had three apples and you ate two then you would have one apples left. I don't think that's high school math.

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A bank in the Bay area is considering a training program for its staff. The probability that a new training program will increas

WITCHER [35]

Answer:

$P(B' \cup A') = P((A \cap B)') = 1-P(A \cap B)= 1-0.32=0.68$

See explanation below.

Step-by-step explanation:

For this case we define first some notation:

A= A new training program will increase customer satisfaction ratings

B= The training program can be kept within the original budget allocation

And for these two events we have defined the following probabilities

$P(A) = 0.8, P(B) = 0.2$

We are assuming that the two events are independent so then we have the following propert:

$P(A \cap B ) = P(A) * P(B)$

And we want to find the probability that the cost of the training program is not kept within budget or the training program will not increase the customer ratings so then if we use symbols we want to find:

$P(B' \cup A')$

And using the De Morgan laws we know that:

$(A \cap B)' = A' \cup B'$

So then we can write the probability like this:

$P(B' \cup A') = P((A \cap B)')$

And using the complement rule we can do this:

$P(B' \cup A') = P((A \cap B)')= 1-P(A \cap B)$

Since A and B are independent we have:

$P(A \cap B )=P(A)*P(B) =(0.8*0.4) =0.32$

And then our final answer would be:

$P(B' \cup A') = P((A \cap B)') = 1-P(A \cap B)= 1-0.32=0.68$

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3 years ago

I low key need halp. Very soon, please send halp. :>

forsale [732]

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Please help I will give brainly and show your work also :)

hoa [83]

Use a calculator what?

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This means as a ratio it is now 6/4 as many as originally planned.

6/4 can be reduced to 3/2.

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This means the length of time the food lasts is reduced by 1/3, which is 33.3%

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