The number of pages which Claire should read each day to finish the 35 pages in 6 days is; 5.833 pages per day.
<h3>How many pages should Claire read per day?</h3>
It follows from the task content that the number of pages which Claire should read per day in a bid to finish all 35 pages in 6 days be determined.
Since the given condition is such that; Claire reads an equal number of pages on each of the next six days.
It follows that the number of pages to be read each day is given by;
35 / 6
= 5.833 pages per day.
Ultimately, the number of pages Claire should read per day over the next 6 days is; 5.833 pages per day.
Read more on division;
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3) x² - 121 = 0
x² = 121
x' = +√121
x' = 11
_______________
x'' = - √121
x'' = -11
Solution ⇒ S{-11 ; 11 } or (x-11)(x+11)
4) 4x² + 144 = 0
4x² = -144
x² = -144 / 4
x² = -36
x = √-36
No solution ⇒ S = ∅
5) z²+10z+21 = 0
Δ = 10² - 4(1)(21)
Δ = 100 - 84
Δ = 16
x' = (-10+4) / 2 = -6/2 = -3
x'' = (-10-4) / 2 = -14/2 = -7
Solution ⇒ S{ -7 ; -3} or (x+3)(x+7)
Answer:
The length of side b is 179 ft
Step-by-step explanation:
Given triangle ABC in which
∠A = 33°, ∠B = 63°, c=200
we have to find the length of b
In ΔABC, by angle sum property of triangle
∠A+∠B+∠C=180°
33°+63°+∠C=180°
∠C=180°-33°-63°=84°
By sine law,
The length of side b is 179 ft
Option C is correct.
Answer:
f(x) = 0.5x + 5
Domain: positive whole numbers
Range: f(x) ≥ 5
Step-by-step explanation:
Let's x denote the total number of fruit juice.
This means that if $0.5 for each fruit juice, then the total cost incurred for fruit juice would be $0.5x.
Since she incurred a cost of $5 for 100 cups and $0.5 for each fruit juice, then the total cost, f(x), would be:
f(x) = 0.5x + 5
The domain would be all positive whole numbers (it is restricted to positive whole numbers because a fruit juice can't be "negative" neither can it be "half").
The range is all numbers equal or greater than 5. This is because, even if she does not eventually get fruit juice, she will still incur a cost of 5usd for cups.
That’s true!!!! They totally should do that!
