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Svet_ta [14]
3 years ago
9

How do I prepare for the PSAT? Every time I take a practice test, I get stuck on a problem that is within my topic range, but fo

r some reason I cannot understand it. Whenever I look at the explanation, I get it, but I cannot do it on my own. Any idea how I can efficiently prepare for it?
Mathematics
1 answer:
melamori03 [73]3 years ago
8 0

Answer:

Maybe you can have someone read it to you to see if you can answer it that way after you answer it on your own a cupple of times

Step-by-step explanation:

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Choose a number between 67 and 113 that is a multiple of 3, 9, and 12
Anestetic [448]
72 is multiples of 3,9, and 12
3 0
3 years ago
The Red Rox have won 3 World Series titles in the last 11 years. At this rate, how long will it take them to win 20 World Series
Alex787 [66]

Answer:

73 1/3 years

Step-by-step explanation:

3 WST = 11 years              FInd the unit rate

1 WST = 11/3

20 WST =  220/3 or 73 1/3 years

<h3><u><em>Hope this helps!!! </em></u></h3><h3><u><em>Please mark this as brainliest!!! </em></u></h3><h3><u><em>Thank You!!! </em></u></h3><h3><u><em>:)</em></u></h3>
8 0
3 years ago
A survey of 76 commercial airline flights of under 2 hours resulted in a sample average late time for a flight of 2.55 minutes.
nika2105 [10]

Answer:

The best point of estimate for the true mean is:

\hat \mu = \bar X = 2.55

2.55-1.96\frac{12}{\sqrt{76}}=-0.148    

2.55+1.96\frac{12}{\sqrt{76}}=5.248    

Since the time can't be negative a good approximation for the confidence interval would be (0,5.248) minutes. The interval are tellling to us that at 95% of confidence the average late time is lower than 5.248 minutes.

Step-by-step explanation:

Information given

\bar X=2.55 represent the sample mean for the late time for a flight

\mu population mean

\sigma=12 represent the population deviation

n=76 represent the sample size  

Confidence interval

The best point of estimate for the true mean is:

\hat \mu = \bar X = 2.55

The confidence interval for the true mean is given by:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

The Confidence level given is 0.95 or 95%, th significance would be \alpha=0.05 and \alpha/2 =0.025. If we look in the normal distribution a quantile that accumulates 0.025 of the area on each tail we got z_{\alpha/2}=1.96

Replacing we got:

2.55-1.96\frac{12}{\sqrt{76}}=-0.148    

2.55+1.96\frac{12}{\sqrt{76}}=5.248    

Since the time can't be negative a good approximation for the confidence interval would be (0,5.248) minutes. The interval are tellling to us that at 95% of confidence the average late time is lower than 5.248 minutes.

7 0
3 years ago
5n + 3 &gt; 4 - (6 – 5n)
jek_recluse [69]
3>-2 i believe
djdjjdksksk sorry i needed more characters
4 0
3 years ago
I’m giving out brainlest to whoever answers this correctly!
borishaifa [10]

Answer:

A. 18.2

Step-by-step explanation:

b^2 + 14^2 = 23^2

b = sqrt(333) = 18.248

5 0
3 years ago
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