I think the answer is 4. 12× 1/3= 4
Answer:
x + 2y ≤ 100 and x + 3y ≤ 400
Maximum profit = 6x + 5y.
Step-by-step explanation:
Let there be x number of small dishes and y number of large dishes to maximize the profit.
So, total profit is P = 6x + 5y .......... (1)
Now, the small dish uses 1 cup of sauce and 1 cup of cheese and the large dish uses 2 cups of sauce and 3 cups of cheese.
So, as per given conditions,
x + 2y ≤ 100 ........ (1) and
x + 3y ≤ 400 .......... (2)
Therefore, those are the constraints for the problem. (Answer)
Answer:
2 for the first drop down
-3 and 1 for the second
Step-by-step explanation:
no u
Answer:
18
Step-by-step explanation:
one half times (four plus eight)
Writing mathematically
1½ ( 4+8)
Using BODMAS
we'll take the bracket first
1½ × 12
Change 1½ to improper fraction = 3/2
3/2 × 12 = 3×6
= 18
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