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xxMikexx [17]
3 years ago
11

The figures below are made out of circles, semicircles, quarter circles, and a square. Find the area and the perimeter of each f

igure and give your answers as a completely simplified exact value in terms of π (no approximations).

Mathematics
2 answers:
Svetach [21]3 years ago
7 0

Answer:

Step-by-step explanation:

Rom4ik [11]3 years ago
3 0

Answer:

  • The area of the figure will be 5π/2 in².
  • The perimeter will be 3π + 2 in

Step-by-step explanation:

This figure is a combination of two semi-circles.

  • One having diameter of 2 inches i.e. AD
  • Other having diameter of 4 inches i.e. AC

As

{\displaystyle \pi ={\frac {C}{d}}}

{{{C}}}=\displaystyle \pi.d

Perimeter of the big figure could be computed by cutting the perimeters of each circle in half, and then combing them together.

Area could be computed using the same way.

<u>Calculating the Perimeter:</u>

  • As the circumference of the smaller circle is 2π in. Cutting it half would yield the circumference of the smaller semi-circle i.e. π.
  • As the circumference of the bigger circle is 4π in. Cutting it half would yield the circumference of the bigger semi-circle i.e. 2π.
  • As the length of the segment DC is 2 in.

So, the total perimeter would be: π + 2π + 2 = 3π + 2 in

<u>Calculating the Area</u>

Area could be computed using the same way as we did during measuring perimeter.

As the area of circle is

A={\displaystyle \pi.r^{2}

As we are dealing with semi-circles. So, cutting the diameters of two semi-circles in half can let us find the radii of them.

So,

  • Smaller semi-circle has 1 in radius
  • Larger semi-circle has 2 in radius

Areas would have to be cut in half as well, as we are dealing with semi-circles.

So,

For smaller:

A_{small} =\frac{1}{2} {\displaystyle \pi.r^{2}

A_{small} =\frac{1}{2} {\displaystyle \pi.(1)^{2}

A_{small} =\frac{1}{2} {\displaystyle \pi

Hence, the area of smaller will be: π/2 in²

For larger:

A_{larger} =\frac{1}{2} {\displaystyle \pi.r^{2}

A_{larger} =\frac{1}{2} {\displaystyle \pi.(2)^{2}

A_{larger} =2 \pi^{}

Hence, the area of larger will be: 2π in²

Combining them together:

\frac{1}{2} {\displaystyle \pi^{} + 2 {\displaystyle \pi^{}=\frac{5}{2} {\displaystyle \pi^{}

Therefore,

  • The area of the figure will be 5π/2 in².
  • The perimeter will be 3π + 2 in

<em>Keywords: radius, area, perimeter, semi-circle, circle, diameter, circumference of circle</em>

<em>Learn more about circle measurements from brainly.com/question/3855576</em>

<em>#learnwithBrainly</em>

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Part A) The system of inequalities is

x\geq2  and  y\geq2

Part B) In the procedure

Part C) The schools that Natalie is allowed to attend are A,B and D

Step-by-step explanation:

Part A: Using the graph above, create a system of inequalities that only contain points C and F in the overlapping shaded regions

we have

Points C(2,2), F(3,4)

The system of inequalities could be

x\geq2 -----> inequality A

The solution of the inequality A is the shaded area at the right of the solid line x=2

y\geq2 -----> inequality B

The solution of the inequality B is the shaded area above of the solid line y=2

see the attached figure N 1

Part B: Explain how to verify that the points C and F are solutions to the system of inequalities created in Part A

we know that

If a ordered pair is a solution of the system of inequalities, then the ordered pair must satisfy both inequalities

<em>Verify point C</em>

C(2,2)    

<em>Inequality A</em>

x\geq2 -----> 2\geq2 ----> is true

<em>Inequality B</em>

y\geq2 ------> 2\geq2 ----> is true

therefore

Point C is a solution of the system of inequalities

<em>Verify point D</em>

F(3,4)    

<em>Inequality A</em>

x\geq2 -----> 3\geq2 ----> is true

<em>Inequality B</em>

y\geq2 ------> 4\geq2 ----> is true

therefore

Point D is a solution of the system of inequalities

Part C: Natalie can only attend a school in her designated zone. Natalie's zone is defined by y < −2x + 2. Explain how you can identify the schools that Natalie is allowed to attend.

we have

y < -2x+2

The solution of the inequality is the shaded area below the dotted line y=-2x+2

The y-intercept of the dotted line is the point (0,2)

The x-intercept of the dotted line is the point (1,0)

To graph the inequality, plot the intercepts and shade the area below the dotted line

see the attached figure N 2

therefore

The schools that Natalie is allowed to attend are A,B and D

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