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xxMikexx [17]
3 years ago
11

The figures below are made out of circles, semicircles, quarter circles, and a square. Find the area and the perimeter of each f

igure and give your answers as a completely simplified exact value in terms of π (no approximations).

Mathematics
2 answers:
Svetach [21]3 years ago
7 0

Answer:

Step-by-step explanation:

Rom4ik [11]3 years ago
3 0

Answer:

  • The area of the figure will be 5π/2 in².
  • The perimeter will be 3π + 2 in

Step-by-step explanation:

This figure is a combination of two semi-circles.

  • One having diameter of 2 inches i.e. AD
  • Other having diameter of 4 inches i.e. AC

As

{\displaystyle \pi ={\frac {C}{d}}}

{{{C}}}=\displaystyle \pi.d

Perimeter of the big figure could be computed by cutting the perimeters of each circle in half, and then combing them together.

Area could be computed using the same way.

<u>Calculating the Perimeter:</u>

  • As the circumference of the smaller circle is 2π in. Cutting it half would yield the circumference of the smaller semi-circle i.e. π.
  • As the circumference of the bigger circle is 4π in. Cutting it half would yield the circumference of the bigger semi-circle i.e. 2π.
  • As the length of the segment DC is 2 in.

So, the total perimeter would be: π + 2π + 2 = 3π + 2 in

<u>Calculating the Area</u>

Area could be computed using the same way as we did during measuring perimeter.

As the area of circle is

A={\displaystyle \pi.r^{2}

As we are dealing with semi-circles. So, cutting the diameters of two semi-circles in half can let us find the radii of them.

So,

  • Smaller semi-circle has 1 in radius
  • Larger semi-circle has 2 in radius

Areas would have to be cut in half as well, as we are dealing with semi-circles.

So,

For smaller:

A_{small} =\frac{1}{2} {\displaystyle \pi.r^{2}

A_{small} =\frac{1}{2} {\displaystyle \pi.(1)^{2}

A_{small} =\frac{1}{2} {\displaystyle \pi

Hence, the area of smaller will be: π/2 in²

For larger:

A_{larger} =\frac{1}{2} {\displaystyle \pi.r^{2}

A_{larger} =\frac{1}{2} {\displaystyle \pi.(2)^{2}

A_{larger} =2 \pi^{}

Hence, the area of larger will be: 2π in²

Combining them together:

\frac{1}{2} {\displaystyle \pi^{} + 2 {\displaystyle \pi^{}=\frac{5}{2} {\displaystyle \pi^{}

Therefore,

  • The area of the figure will be 5π/2 in².
  • The perimeter will be 3π + 2 in

<em>Keywords: radius, area, perimeter, semi-circle, circle, diameter, circumference of circle</em>

<em>Learn more about circle measurements from brainly.com/question/3855576</em>

<em>#learnwithBrainly</em>

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(a) By inspection, find a particular solution of y'' + 2y = 14. yp(x) = (b) By inspection, find a particular solution of y'' + 2
SOVA2 [1]

Answer:

(a) The particular solution, y_p is 7

(b) y_p is -4x

(c) y_p is -4x + 7

(d) y_p is 8x + (7/2)

Step-by-step explanation:

To find a particular solution to a differential equation by inspection - is to assume a trial function that looks like the nonhomogeneous part of the differential equation.

(a) Given y'' + 2y = 14.

Because the nonhomogeneus part of the differential equation, 14 is a constant, our trial function will be a constant too.

Let A be our trial function:

We need our trial differential equation y''_p + 2y_p = 14

Now, we differentiate y_p = A twice, to obtain y'_p and y''_p that will be substituted into the differential equation.

y'_p = 0

y''_p = 0

Substitution into the trial differential equation, we have.

0 + 2A = 14

A = 6/2 = 7

Therefore, the particular solution, y_p = A is 7

(b) y'' + 2y = −8x

Let y_p = Ax + B

y'_p = A

y''_p = 0

0 + 2(Ax + B) = -8x

2Ax + 2B = -8x

By inspection,

2B = 0 => B = 0

2A = -8 => A = -8/2 = -4

The particular solution y_p = Ax + B

is -4x

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Let y_p = Ax + B

y'_p = A

y''_p = 0

0 + 2(Ax + B) = -8x + 14

2Ax + 2B = -8x + 14

By inspection,

2B = 14 => B = 14/2 = 7

2A = -8 => A = -8/2 = -4

The particular solution y_p = Ax + B

is -4x + 7

(d) Find a particular solution of y'' + 2y = 16x + 7

Let y_p = Ax + B

y'_p = A

y''_p = 0

0 + 2(Ax + B) = 16x + 7

2Ax + 2B = 16x + 7

By inspection,

2B = 7 => B = 7/2

2A = 16 => A = 16/2 = 8

The particular solution y_p = Ax + B

is 8x + (7/2)

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3 years ago
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