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Nat2105 [25]
4 years ago
5

it says "use the given information to write an equation for each line" but I don't understand what to do, please help.

Mathematics
1 answer:
Gwar [14]4 years ago
7 0
USe the points and slope to write in y=mx+b!
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PLS ANSWER ASAPPPPPP
SCORPION-xisa [38]

Option D equal is your answer ☺️☺️☺️

8 0
3 years ago
How i can answer this question, NO LINKS, if you answer correctly i will give u brainliest!
mel-nik [20]

Answer:

The answer is 8

x=3

4^3/2^3=8

6 0
3 years ago
This doesn’t make sense explain plz
AnnZ [28]

Its simple, graph them.

For the first equation, go on the Y-Axis (the vertical one) and go to 4. Then from there go up 1, right 6.

For the second equation go on the Y-Axis (the vertical one) and plot a point at 1 (aka 0,1) Now you go up 1, right 3.

When you see an equation like y=2x+3, the 3 represents the point (0,3) as when the x is 0, y=3. Just plug the numbers in. And as for the "2x" 2 is the slope. Slope is always rise/run or up, then right. So if its 2 your slope is 2/1, rise 2, over 1. If it "-2x" is your slope then all you have to do is go down 2, right 1.

I hope this cleared up your confusion, brainliest/heart would help.

5 0
3 years ago
In Ms.Khans class,22 out of 25 students hand in their projects on time. What percent of the class hand in their projects on time
Nikitich [7]

88 % students of the class hand in their projects on time

<em><u>Solution:</u></em>

Given that, Ms.Khans class, 22 out of 25 students hand in their projects on time

Total number students = 25

Students hand in their projects on time = 22

<em><u>To find: percent of the class hand in their projects on time</u></em>

\text{ percent of class hand in time } = \frac{\text{Students hand in projects on time}}{\text{total students}} \times 100

Substituting the values, we get

\text{ percent of class hand in time } = \frac{22}{25} \times 100\\\\\text{ percent of class hand in time } = 0.88 \times 100\\\\\text{ percent of class hand in time } = 88

Thus 88 % students of the class hand in their projects on time

5 0
3 years ago
Tan x + tan 2x = 0
choli [55]

stated method in question is wrong!

<u>Step-by-step explanation:</u>

We need to find the general solution of x ! for the equation tan x + tan 2x = 0

⇒  tan x + tan 2x = 0

⇒  (tan x + tan 2x)-tan2x = 0-tan2x

⇒  tan x = -tan2x

Now , we know that tan(\pi -2x) = -tan2x

⇒  tan x = -tan2x

⇒  tan x = tan(\pi -2x)

Now , we know that TanA = TanB \\A=B

⇒  tan x = tan(\pi -2x)

⇒  x = \pi -2x

⇒  3x = \pi

⇒  x = \frac{\pi}{3}     ......(1)

General solution of Tan x is : x = n\pi + \alpha , \

Here , from equation (1) we get  \alpha =\frac{\pi }{3} . Hence general solution is :

⇒ x = n\pi +\frac{\pi }{3} .Therefore , stated method in question is wrong!

4 0
3 years ago
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