Answer:
h
Step-by-step explanation:
j
Answer:
A and C
Step-by-step explanation:
A and C can be any number because the equation ends with x=x
Answer:
Please find attached the required circle
It is observed that the angle subtended by the arc CB which are m∠CAB and m∠CDB is such that the angle arc CB subtends at the center, m∠CAB is two times the angle that the arc CB subtends at the circumference
The measured angle subtended by the arc CB at the center m∠CAB = 64° and the measured angle subtended by the arc CB at the circumference m∠CDB = 32°
Step-by-step explanation:
T
Let x =lenght, y = width, and z =height
<span>The volume of the box is equal to V = xyz </span>
<span>Subject to the surface area </span>
<span>S = 2xy + 2xz + 2yz = 64 </span>
<span>= 2(xy + xz + yz) </span>
<span>= 2[xy + x(64/xy) + y(64/xy)] </span>
<span>S(x,y)= 2(xy + 64/y + 64/x) </span>
<span>Then </span>
<span>Mx(x, y) = y = 64/x^2 </span>
<span>My(x, y) = x = 64/y^2 </span>
<span>y^2 = 64/x </span>
<span>(64/x^2)^2 = 64 </span>
<span>4096/x^4 = 64/x </span>
<span>x^3 = 4096/64 </span>
<span>x^3 = 64 </span>
<span>x = 4 </span>
<span>y = 64/x^2 </span>
<span>y = 4 </span>
<span>z= 64/yx </span>
<span>z= 64/16 </span>
<span>z = 4 </span>
<span>Therefor the dimensions are cube 4.</span>
Answer:35
Simplifying
5(x + 20) = 7x + 30
Reorder the terms:
5(20 + x) = 7x + 30
(20 * 5 + x * 5) = 7x + 30
(100 + 5x) = 7x + 30
Reorder the terms:
100 + 5x = 30 + 7x
Solving
100 + 5x = 30 + 7x
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '-7x' to each side of the equation.
100 + 5x + -7x = 30 + 7x + -7x
Combine like terms: 5x + -7x = -2x
100 + -2x = 30 + 7x + -7x
Combine like terms: 7x + -7x = 0
100 + -2x = 30 + 0
100 + -2x = 30
Add '-100' to each side of the equation.
100 + -100 + -2x = 30 + -100
Combine like terms: 100 + -100 = 0
0 + -2x = 30 + -100
-2x = 30 + -100
Combine like terms: 30 + -100 = -70
-2x = -70
Divide each side by '-2'.
x = 35
Simplifying
x = 35
Hope it helps. Please tell me if im correct
