The price of the pear is $0.6
Given:
The total cost of lunch is $3.50, consisting of a juice, a sandwich, and a pear.The juice cost 1.5 times as much as the pear.The sandwich costs $1.40 more than the pear.
From above statements
Juice + sandwich + pear = $3.50 -----------eq(1)
Juice = 1.5 * pear
sandwich = pear + $1.40
substitute juice and sandwich values in eq(1)
1.5 pear + pear + $1.40 + pear = $3.50
3.5 pear = $3.50 - $1.40
pear = $2.10/3.5
pear = $0.60
Hence the price of the pear is $0.6
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Answer:
p=-9
Step-by-step explanation:
132=-6+3 (1-5p)
-6+3 (1-5p)=132
-6+3 (1-5p)+6=132+6
3(1-5p)=138
3(1-5p)/3=138/3
1-5p=46
1-5p-1=46-1
-5p=45
p=-9

Use the rational zero theorem
In rational zero theorem, the rational zeros of the form +-p/q
where p is the factors of constant
and q is the factors of leading coefficient

In our f(x), constant is 2 and leading coefficient is 14
Factors of 2 are 1, 2
Factors of 14 are 1,2, 7, 14
Rational zeros of the form +-p/q are

Now we separate the factors


We ignore the zeros that are repeating

Option A is correct
The objective function is simply a function that is meant to be maximized. Because this function is multivariable, we know that with the applied constraints, the value that maximizes this function must be on the boundary of the domain described by these constraints. If you view the attached image, the grey section highlighted section is the area on the domain of the function which meets all defined constraints. (It is all of the inequalities plotted over one another). Your job would thus be to determine which value on the boundary maximizes the value of the objective function. In this case, since any contribution from y reduces the value of the objective function, you will want to make this value as low as possible, and make x as high as possible. Within the boundaries of the constraints, this thus maximizes the function at x = 5, y = 0.