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77julia77 [94]
3 years ago
8

WORTH 10 POINTS! 1)susan can type 4 pages of text in 10 minutes.Assuming she types at a constant rate,write the linear equation

that represents the
situation
2)phil can build 3 birdhouses in 5 days.Assuming he builds birdhouses at a constant rate,write the linear equation that represents the situation.
3)train a can travel a distance of 500 miles in 8 hours.Assuming the train travels at a constant rate write a linear equation that represents the situation.
4)Natalie can paint 40 square feet in 9 minutes Assuming she paints at a constant rate write the linear equation that represents the situation.
5)bianca can run 5 miles in 41 minutes assuming she runs at a constant rate write the linear equation that represents the situation
6)Geoff can mow an entire lawn of 450 square ft in 30 minutes.Assuming he mows at a constant rate,write the linear equation that represents the situation.
(TRY TO ANSWER ALL OF THEM!! write a linear equation for all:)
Mathematics
1 answer:
Minchanka [31]3 years ago
8 0
1) pages per minute is the rate. the rate is the slope pages/minutes = .4
y=.4x or y=2/5(x)
2)birdhouses per day is the slope. = .6
y=.6x or y=3/5(x)
3) miles per hour is the slope. 500/8=62.5
y=62.5x
4) square feet per minute is the slope. 40/9 =4.444444444
y=4.4444444444x or y=40/9(x)
5)miles per minutes is the rate. 5/41 is the slope. 
y=5/41(x)
6) the rate is square feet per minute. 450/30=15
y=15x
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Which ordered pairs are in the solution set of the system of linear inequalities?
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Answer:

C

Step-by-step explanation:

The solution to the system of the inequalities lies in the shaded region between the 2 lines.

The ordered pairs (5, - 2), (3, 1), (4, 2) lie within this region ⇒ C

8 0
3 years ago
The boundary of a lamina consists of the semicircles y = 1 − x2 and y = 16 − x2 together with the portions of the x-axis that jo
oksano4ka [1.4K]

Answer:

Required center of mass (\bar{x},\bar{y})=(\frac{2}{\pi},0)

Step-by-step explanation:

Given semcircles are,

y=\sqrt{1-x^2}, y=\sqrt{16-x^2} whose radious are 1 and 4 respectively.

To find center of mass, (\bar{x},\bar{y}), let density at any point is \rho and distance from the origin is r be such that,

\rho=\frac{k}{r} where k is a constant.

Mass of the lamina=m=\int\int_{D}\rho dA where A is the total region and D is curves.

then,

m=\int\int_{D}\rho dA=\int_{0}^{\pi}\int_{1}^{4}\frac{k}{r}rdrd\theta=k\int_{}^{}(4-1)d\theta=3\pi k

  • Now, x-coordinate of center of mass is \bar{y}=\frac{M_x}{m}. in polar coordinate y=r\sin\theta

\therefore M_x=\int_{0}^{\pi}\int_{1}^{4}x\rho(x,y)dA

=\int_{0}^{\pi}\int_{1}^{4}\frac{k}{r}(r)\sin\theta)rdrd\theta

=k\int_{0}^{\pi}\int_{1}^{4}r\sin\thetadrd\theta

=3k\int_{0}^{\pi}\sin\theta d\theta

=3k\big[-\cos\theta\big]_{0}^{\pi}

=3k\big[-\cos\pi+\cos 0\big]

=6k

Then, \bar{y}=\frac{M_x}{m}=\frac{2}{\pi}

  • y-coordinate of center of mass is \bar{x}=\frac{M_y}{m}. in polar coordinate x=r\cos\theta

\therefore M_y=\int_{0}^{\pi}\int_{1}^{4}x\rho(x,y)dA

=\int_{0}^{\pi}\int_{1}^{4}\frac{k}{r}(r)\cos\theta)rdrd\theta

=k\int_{0}^{\pi}\int_{1}^{4}r\cos\theta drd\theta

=3k\int_{0}^{\pi}\cos\theta d\theta

=3k\big[\sin\theta\big]_{0}^{\pi}

=3k\big[\sin\pi-\sin 0\big]

=0

Then, \bar{x}=\frac{M_y}{m}=0

Hence center of mass (\bar{x},\bar{y})=(\frac{2}{\pi},0)

3 0
3 years ago
G(x) = –16x + x2 in vertex form.
Citrus2011 [14]

Answer:

g(x)=(x-8)^2-64

Step-by-step explanation:

The given function is;

g(x)=-16x+x^2

This is the same as;

g(x)=x^2-16x

Add and subtract the square of half the coefficient of x.

g(x)=x^2-16x+(-8)^2-(-8)^2

Observe that the first three terms is a perfect square trinomial.

g(x)=(x-8)^2-64

The vertex form is g(x)=(x-8)^2-64

The vertex (8,-64)

8 0
3 years ago
What is the next term in the sequence 7,12,17,22,...
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27
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3 years ago
Read 2 more answers
A restaurant owner was experimenting with the taste of her homestyle lemon drink. She started with 60 litres of water. She remov
Burka [1]

Answer:

ratio of pure lemon juice to water in the homestyle lemon  drink is 5 : 19.

Step-by-step explanation:

In order to solve the final ratio of lemon juice to water, let us start by determining the initial ratio of pure lemon juice to water in the first mix. This is done as follows:

Total volume of mixture = 60 liters

initial volume of water = 60 liters

initial volume of lemon juice = 0 liters

1) She removed 15 liters of the water and replaced it with 15 liters of pure lemon juice.

Volume of water = 60 - 15 = 45 liters

Volume of lemon juice = 15 liters

 \therefore \frac{15}{60}\ = \frac{1}{4}\  of\ the\ first\ mix\ is\ lemon\ juice\\\frac{45}{60}\ = \frac{3}{4}\  of\ the\ first\ mix\ is\ pure\ water

2) She removed 10 liters of the new mixture

Let us convert this amount removed into ratio:

lemon\ juice\ = \frac{1}{4}\ \times 10 = \frac{10}{4} = \frac{5}{2}\ liters.\\  \therefore the\ owner\ removes\ \frac{5}{2}\ liters\ of\ pure\ lemon\ juice\\pure\ water\ = \frac{3}{4}\ \times 10 = \frac{30}{4} = \frac{15}{2}\ liters\\  \therefore\ the\ owner\ removes\ \frac{15}{2}\ liters\ of\ water\ from\ the\ first\ mix.

New volumes of water and lemon juice after removing the 10 liters of mixture is calculated as follows:

lemon\ juice\ = 15 - \frac{5}{2} = \frac{30-5}{2} = \frac{25}{2}\ liters\ of\ lemon\ juice\\pure\ water\ = 45 - \frac{15}{2} = \frac{90-15}{2} = \frac{75}{2}\ liters\ of\ pure\ water

3) and replaced it with 10 liters of water.

New\ volume\ of\ water\ = 10 + \frac{75}{2} = \frac{20+ 75}{2} = \frac{95}{2}\ liters

The final ratio of lemon juice to water:

\frac{25}{2} : \frac{95}{2}\\= 25 : 95\\= 5 : 19

Therefore, the final ratio of pure lemon juice to water in the homestyle lemon  drink is 5 : 19.

4 0
3 years ago
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