Ask question

Ask question

All categories

2 years ago

5

Simplify 3 3/4- 1/5

1 answer:

gulaghasi [49]2 years ago

7 0

Answer: 3 11/20

Step-by-step explanation:

You would first simplify 3 3/4 which is 15/4 then you would subtract it with 1/5

Next, you would have to find the GCD ( greatest common factor) for 15/4 and 1/5 which is 20 so multiply 15 by 5 and 4 by 5 which is 75/20, then multiply the top and bottom with 4 for 1/5 which is 4/20 . You then would subtract the simplified forms 75/20 with 4/20 Which is 71/20 which u can simplify to

3 11/20.

You might be interested in

Please help me!!! Will get brainliest!!!

kaheart [24]

The graph does not support his claim. The vertical scale does not start At 0 which distorts the percent of change.

4 0

3 years ago

Read 2 more answers

What is the value in 4s in 14,423

Savatey [412]

In the number 14,423, the digit '4' comes up twice, in the thousand and hundred position.

The farther to the left a digit is, the higher that number is compared to another digit to the right of it.

This is why 1,000 is higher than 999.

In the number 14,423, there are two values for four: thousand (four thousand) and hundred (four hundred)

3 0

2 years ago

Read 2 more answers

Scott and Letitia are brother and sister. After dinner, they have to do the dishes, with one washing and the other drying. They

ehidna [41]

Answer:

The probability that Scott will wash is 2.5

Step-by-step explanation:

Given

Let the events be: P = Purple and G = Green

$P = 2$

$G = 3$

Required

The probability of Scott washing the dishes

If Scott washes the dishes, then it means he picks two spoons of the same color handle.

So, we have to calculate the probability of picking the same handle. i.e.

$P(Same) = P(G_1\ and\ G_2) + P(P_1\ and\ P_2)$

This gives:

$P(G_1\ and\ G_2) = P(G_1) * P(G_2)$

$P(G_1\ and\ G_2) = \frac{n(G)}{Total} * \frac{n(G)-1}{Total - 1}$

$P(G_1\ and\ G_2) = \frac{3}{5} * \frac{3-1}{5- 1}$

$P(G_1\ and\ G_2) = \frac{3}{5} * \frac{2}{4}$

$P(G_1\ and\ G_2) = \frac{3}{10}$

$P(P_1\ and\ P_2) = P(P_1) * P(P_2)$

$P(P_1\ and\ P_2) = \frac{n(P)}{Total} * \frac{n(P)-1}{Total - 1}$

$P(P_1\ and\ P_2) = \frac{2}{5} * \frac{2-1}{5- 1}$

$P(P_1\ and\ P_2) = \frac{2}{5} * \frac{1}{4}$

$P(P_1\ and\ P_2) = \frac{1}{10}$

<em>Note that: 1 is subtracted because it is a probability without replacement</em>

So, we have:

$P(Same) = P(G_1\ and\ G_2) + P(P_1\ and\ P_2)$

$P(Same) = \frac{3}{10} + \frac{1}{10}$

$P(Same) = \frac{3+1}{10}$

$P(Same) = \frac{4}{10}$

$P(Same) = \frac{2}{5}$

8 0

2 years ago

Find the measure of angle d.<br> d°

QveST [7]

Answer:

Need points sorry <3

Step-by-step explanation:

3 0

2 years ago

All 3,000 seats in a theater are being replaced. So far, 5 sections 136 seats and a sixth section containing 348 seats have been

Ostrovityanka [42]

1,124 seats still need to be replaced.

7 0

3 years ago

Read 2 more answers