Question

Seven more than the quotient of a number b and 45 is greater than 5.

Answer 1

Answer/Step-by-step explanation:

Given:

Seven more than the quotient of a number b and 45 is greater than 5

So:

Seven more than the quotient of a number b and 45 is greater than 5

=

7 + b/45 > 5

Solve if needed:

$\begin{bmatrix}\mathrm{Solution:}\:&\:b > -90\:\\ \:\mathrm{Interval\:Notation:}&\:\left(-90,\:\infty \:\right)\end{bmatrix}$

$\mathrm{Subtract\:}7\mathrm{\:from\:both\:sides}$

$7+\frac{b}{45}-7 > 5-7$

$\mathrm{Simplify}$

$\frac{b}{45} > -2$

$\mathrm{Multiply\:both\:sides\:by\:}45$

$\frac{45b}{45} > 45\left(-2\right)$

$\mathrm{Simplify}$

$b > -90$

~Lenvy~