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Alekssandra [29.7K]
3 years ago
7

Name the vertex of <4

Mathematics
1 answer:
snow_tiger [21]3 years ago
7 0
You would do 75/ 3 to find the cost of 1 ticket. You would then times that number by 8 to find what 8 tickets will cost.
In this situation you would do 75 divided by 3 which equals 25. Then you would do 25 multiplies by 8 which gives you 200. So the answer is £200
Hope that helped you x
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The monthly cost of driving a car depends on the number of miles driven. Lynn found that in May her driving cost was $380 for 48
andrezito [222]

Answer:

y=0.2x+284

Step-by-step explanation:

Let  x be the distance driven, d-distance and C our constant.

Our information can be presented as:

y=mx+c\\\\450=830x+C\ \ \ \ \ \ \ \ \ eqtn 1\\\\380=480x+C\ \ \ \ \ \ \ \ \ eqtn 2

#Subtracting equation 2 from 1:

70=350x\\x=0.2

Hence the fixed cost per mile driven,x is $0.20

To find the constant,C we substitute x in any of the equations:

450=830x+C\ \ \ \ \ \ \ X=0.2\\\therefore C=450-830\times0.2\\=284

Now, substituting our values in the linear equation:

y=0.2x+284       #y=cost of driving, x=distance driven

Hence the linear equation for the cost of driving is y+0.2x+284

7 0
3 years ago
Some parts of California are particularly earthquake-prone. Suppose that in one metropolitan area, 33% of all homeowners are ins
Lina20 [59]

Answer:

(a) The probability mass function of <em>X</em> is:

P(X=x)={4\choose x}\ (0.33)^{x}\ (1-0.33)^{4-x};\ x=0,1,2,3...

(b) The most likely value for <em>X</em> is 1.32.

(c) The probability that at least two of the four selected have earthquake insurance is 0.4015.

Step-by-step explanation:

The random variable <em>X</em> is defined as the number among the four homeowners  who have earthquake insurance.

The probability that a homeowner has earthquake insurance is, <em>p</em> = 0.33.

The random sample of homeowners selected is, <em>n</em> = 4.

The event of a homeowner having an earthquake insurance is independent of the other three homeowners.

(a)

All the statements above clearly indicate that the random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> = 4 and <em>p</em> = 0.33.

The probability mass function of <em>X</em> is:

P(X=x)={4\choose x}\ (0.33)^{x}\ (1-0.33)^{4-x};\ x=0,1,2,3...

(b)

The most likely value of a random variable is the expected value.

The expected value of a Binomial random variable is:

E(X)=np

Compute the expected value of <em>X</em> as follows:

E(X)=np

         =4\times 0.33\\=1.32

Thus, the most likely value for <em>X</em> is 1.32.

(c)

Compute the probability that at least two of the four selected have earthquake insurance as follows:

P (X ≥ 2) = 1 - P (X < 2)

              = 1 - P (X = 0) - P (X = 1)

              =1-{4\choose 0}\ (0.33)^{0}\ (1-0.33)^{4-0}-{4\choose 1}\ (0.33)^{1}\ (1-0.33)^{4-1}\\\\=1-0.20151121-0.39700716\\\\=0.40148163\\\\\approx 0.4015

Thus, the probability that at least two of the four selected have earthquake insurance is 0.4015.

3 0
3 years ago
What is the slope of the line?<br><br> no slope<br> 1<br> 0<br> -2
morpeh [17]

Answer:

0

Step-by-step explanation:

4 0
3 years ago
If a toy truck is created in a 2:9 scale, and the wheel of the toy is 14cm wide, how wide is the actual wheel?
lesya [120]

Answer:63 cm

Step-by-step explanation:

Given

The scale of creation is 2:9

The width of the toy wheel is 14 cm

Suppose x is the actual width of the truck

\therefore \dfrac{2}{9}=\dfrac{14}{x}\\\\\Rightarrow x=\dfrac{9}{2}\times 14=63\ cm

Thus, the width of actual truck is 63 cm

8 0
3 years ago
Alonso went to the market with $55 to buy eggs and sugar. He knows he needs a package of 12 eggs that
Inessa05 [86]
It would possibly be a but also b you’re welcome
3 0
3 years ago
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