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3 years ago

Express 2028 as a product of prime factors

Mathematics

1 answer:

Aneli [31]3 years ago

5 0

2028 is result of power of 2. It's exactly 2 ^ 11, so it is 2*2*2*2*2*2*2*2*2*2*2

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34 divided by 3 3/4 equals what in fraction form

anygoal [31]

Answer:

9.06

Step-by-step explanation:

6 0

3 years ago

PLEASEE help me please I’m so confused :( marking the first best answer as brainliest

mixas84 [53]

I wrote it roughly.

Hope it helps.

I am sorry.

7 0

2 years ago

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A student S is suspected of cheating on exam, due to evidence E of cheating being present. Suppose that in the case of a cheatin

Kay [80]

Answer:

Step-by-step explanation:

Suppose we think of an alphabet X to be the Event of the evidence.

Also, if Y be the Event of cheating; &

Y' be the Event of not involved in cheating

From the given information:

$P(\dfrac{X}{Y}) = 60\% = 0.6$

$P(\dfrac{X}{Y'}) = 0.01\% = 0.0001$

$P(Y) = 0.01$

Thus, $P(Y') \ will\ be = 1 - P(Y)$

P(Y') = 1 - 0.01

P(Y') = 0.99

The probability of cheating & the evidence is present is = P(YX)

$P(YX) = P(\dfrac{X}{Y}) \ P(Y)$

$P(YX) =0.6 \times 0.01$

$P(YX) =0.006$

The probabilities of not involved in cheating & the evidence are present is:

$P(Y'X) = P(Y') \times P(\dfrac{X}{Y'})$

$P(Y'X) = 0.99 \times 0.0001 \\ \\ P(Y'X) = 0.000099$

(b)

The required probability that the evidence is present is:

P(YX or Y'X) = 0.006 + 0.000099

P(YX or Y'X) = 0.006099

(c)

The required probability that (S) cheat provided the evidence being present is:

Using Bayes Theorem

$P(\dfrac{Y}{X}) = \dfrac{P(YX)}{P(Y)}$

$P(\dfrac{Y}{X}) = \dfrac{P(0.006)}{P(0.006099)}$

$P(\dfrac{Y}{X}) = 0.9838$

5 0

3 years ago

Help.....././././////////././.

alexgriva [62]

Answer:

hello, i am not sure. but the answer is between a and c

Step-by-step explanation:

5 0

2 years ago

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In your last 23 basketball games, you attempted 101 free throws and made 66. Find the experimental probability that you make a f

WARRIOR [948]

Experimental probability is the chance an event has to occur. It is derived from the number of times an event occurs to the total number of trials. You can use the following formula to calculate it. P = (o/t) * 100%, where o is the number of times the event occurred, and t is the total amount of trials ran. In this case, P = (66/101) * 100, which evaluates to P = 65.3% (after rounding)
Answer: 65.3%

7 0

3 years ago

Read 2 more answers