Question

Write code that prints: Ready! countNum ... 2 1 Blastoff! Your code should contain a for loop. Print a newline after each number and after each line of text Ex: countNum = 3 outputs: Ready! 3 2 1 Blastoff!

Answer 1

Answer:

C# code:

#include <stdio.h>

// start main function

int main()

{

  // declare the required variables

  int userNum = 0;

  int i = 0;

  // set userNum to 3

  userNum = 3;

  // print the 'Ready!'

  printf("Ready!");

  // print the new line

  printf("\n");

  // use the for-loop to print userNum ... 2 1

  for (i = userNum; i >= 1; i--)

  {

      // print current value of i

      printf("%d", i);

      // print the new line

      printf("\n");

  } // end for-loop

  // print the 'Blastoff!'

  printf("Blastoff!");

  // print the new line

  printf("\n");

 

  // return from the program

  return 0;

} // end of main function

Explanation:

Answer 2

Answer:

import java.util.Scanner;

public class BlastOff {

   public static void main(String[] args) {

    Scanner in = new Scanner(System.in);

       System.out.print("Enter Count Down Number: ");

       int countNum = in.nextInt();

       System.out.println("Ready!");

       for(int i = countNum; i>0; i--){

           System.out.println(i);

       }

       System.out.println("Blastoff!");

   }

}

Explanation:

Using Java programming language:

• Prompt and receive count down number from the user using the scanner class
• Print the string Ready! System.out.println("Ready!");
• Using a for loop Output the numbers from the variable countNum down to 1
• Outside of the for loop print Blastoff! System.out.println("Blastoff!");
• All outputs are on  seperate lines by using .println()